Solution (1) using angles of sectors:
Area of A = pi r^2 x 90/360 = 4.9
Area of B = pi r^2 x 270/360 = 14.2
Check: Area of A/B = 4.9/14.72 = 1/3 (as given)
Solution (2) using given info:
Area of B + Area of A = area of circle
Area of B + 1/3 Area of B = 3.14 * (2.5)^2 = 19.625
4/3 Area of B = 19.625
Area of B = 3/4 * 19.625
Area of B = 14.72
Area of A = 1/3 * 14.72 = 4.9
There is more solutions to this problem , like polar coordinate integration , and so on. for more just request.
Answer:51 Groups
Step-by-step explanation:
60 students + 42 students = 102
102 divided by 2 = 51 Total groups.
After the 3rd pick we have: 4 white, 3 red and 8 black marbles.
The probability that the 4th marble is black is:
P ( Black ) = 8 / 15 = 0.5333
After the 4th pick we have: 4 white, 3 red and 7 black marbles.
P ( Red or Black ) = 10 / 14 = 5 / 7 = 0.7143
Answer:
the rate of change of the water depth when the water depth is 10 ft is; 
Step-by-step explanation:
Given that:
the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.
We are meant to find the rate of change of the water depth when the water depth is 10 ft.
The diagrammatic expression below clearly interprets the question.
From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t
Then the similar triangles ΔOCD and ΔOAB is as follows:
( similar triangle property)


h = 2.5r

The volume of the water in the tank is represented by the equation:



The rate of change of the water depth is :

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec
Then,

Therefore,

the rate of change of the water at depth h = 10 ft is:




Thus, the rate of change of the water depth when the water depth is 10 ft is; 
Answer:
Well in set A, all of the sides are the same length but they are different shapes.
In set B, all of the angles are the same, they are just differnet shapes.
Hope this helps! :)