The answer is 9 center is ( 1,0)
Answer:
yes
Step-by-step explanation:
8705/1000 = 8705*0.001
8.705 = 8.705
Answer:

Step-by-step explanation:
Write down the problem;

Simplify

Convert so that the fractions have a common denominator; multiply the numerator and denominator of both fractions such that the denominators are equal;

Add the fractions;

Convert to mixed number;

The chance of picking a almond cookie the first time:
you have 6 cookies, 3 of them are almond
So the chance of taking an almond cookie is

The second time there are 5 cookies left, 2 of them are almond cookies
The chance of taking an almond cookie is

To know the probability of picking two almond cookies in a row, multiply the changes:

The chance of taking two almond cookies is 1/5
Answer:
B. 4 squared
Step-by-step explanation:
You have to use PEMDAS. The first one is P for parenthesis, that is the first operation you have to do.