If you would like to solve for x, you can do this using the following steps:
3x / 6 + 1 = 7
3x / 6 = 7 - 1
x/2 = 6 /*2
x = 6 * 2 = 12
The correct result would be x = 12.
Answer:
-8
Step-by-step explanation:
For roots r and s, the quadratic can be factored ...
f(x) = (x -r)(x -s) = x^2 -(r+s)x +rs
Then the value of r^2+s^2 can be determined from the coefficient of x (-(r+s)) and the constant (rs) by ...
r^2 +s^2 = (-(r+s))^2 -2(rs) = (r^2 +2rs +s^2) -2rs = r^2 +s^2
Comparing this to your given equation, we have the coefficient of x as (-2m) and the constant term as (m^2+2m+3). Forming the expression ...
(x-coefficient)^2 -2(constant term)
we get ...
r^2 +s^2 = (-2m)^2 -2(m^2 +2m +3) = 2m^2 -4m -6
r^2 +s^2 = 2(m -1)^2 -8
The minimum value of this quadratic expression is where m=1 and the squared term is zero. That minimum value is -8.
You can see that the two small angles are close to the 43 degree angle they are both acute while the other is obtuse. Now i'm only in Tenth grade and i read certain letters backwards so i may mix you up but i'ma try.
B should be a 40 degree angle or lower i dont know i dont have my protractor when i need it.
i cant give you the other two cause its too blury to read
If f(x)=3x∧3 and g(x)=-2x∧2 then
F(g(x))= 3(-2x∧2)∧3 = - 3*8*x∧6= - 24x∧6
The correct answer is B.
Good luck!!!
A. Since a rotation across the x axis usually is (x, -y)