Question

The ages (in years) of the 6 employees at a particular computer store are 44, 46, 40, 34, 29, 41

Answer 1

step 1
compute the average: add the values and divide by 6
Average =(44+ 46+40+34+29+41)/6=39

step 2
Compute the deviations from the average
dev: (44-39)=5,
dev: (46-39)=7
dev: (40-39)=1
dev: (34-39)=-5
dev: (29-39)=-10
dev: (41-39)=2

step 3
Square the deviations and add
sum (dev^2): 5^2+7^2+1^2+-5^2+-10^2+2^2
sum (dev^2): 25+49+1+25+100+4-----> 204

step 4
Divide step #3 by the sample size=6
(typically you divide by sample size-1 to get the sample standard deviation,
 but you are assuming the 6 values are the population,
so
no need to subtract 1, from the sample size.
This result is the variance
Variance =204/6=34

step 5
Standard deviation = sqrt(variance)
standard deviation= √(34)------> 5.83

the answer is
5.83