First, I should point out that g(x) should be written as g(x)=(x+2)/3, otherwise the problem is confusing.
(A)
(B) Since and
, it holds that
for all x. This means the composed functions are *identical*
Cody has 7/8 pound of cheese. he uses 1/7 since there are 16 ounces in a pound how much is left
1 answer:
Step One
Find the fraction left.
Starting amount = 7/8 pound
Used amount = 1/7 of a pound.
The common denominator of these two fractions is 8 * 7 = 56
Amount left = amount started with - amount used
Amount left = 7/8 - 1/7
Amount left =
Amount left =
Amount left = 41 / 56 pounds
Step Two
Convert the Answer to ounces.
Ounces = (41/56) * 16
Ounces = 11.71 ounces almost 11 3/4
Find the fraction left.
Starting amount = 7/8 pound
Used amount = 1/7 of a pound.
The common denominator of these two fractions is 8 * 7 = 56
Amount left = amount started with - amount used
Amount left = 7/8 - 1/7
Amount left =
Amount left =
Amount left = 41 / 56 pounds
Step Two
Convert the Answer to ounces.
Ounces = (41/56) * 16
Ounces = 11.71 ounces almost 11 3/4
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Answer:
The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).
Step-by-step explanation:
In a random sample of 300 boards the number of boards that fall outside the specification is 12.
Compute the sample proportion of boards that fall outside the specification in this sample as follows:
The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:
The critical value of <em>z</em> for 95% confidence level is,
*Use a <em>z</em>-table.
Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:
Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).
