Question

The spinner is equally likely to land on any of the six sections.

Answer 1

$|\Omega|=6\\ |A|=\underbrace{2}_{\text{greater than 4}}+\underbrace{3}_{\text{shaded}}-\underbrace{1}_{\text{shaded 5}}=4\\\\ P(A)=\dfrac{4}{6}=\dfrac{2}{3}$

Answer 2

Given that there are 6 sections so possible number of outcomes are 6.

We need a number greater than 4 or on a shaded section.

number greater than 4 are "5,6".

Shaded numbers are "1,3,5".

"OR" means any of above outcomes is favorable i.e. "1,3,5,6" are favorable outcomes.

number of favorable outcomes = 4

Probability is basically "[favorable number of outcome] / [total number of outcomes]"

Hence probability that the spinner will land on a number greater than 4 or on a shaded section is 4/6 which can be simplified to 2/3.

So 2/3 is the final answer.