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Sergeu [11.5K]
3 years ago
13

I will give BRAINLIEST to whoever is correct.

Mathematics
1 answer:
Leni [432]3 years ago
8 0
6 units down. Because you have to go from 3 to 0 which is 3 and from 0 to -3 which is another 3. 3+3=6 :)
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Prove that: √(sec x + 1)/(sec x - 1) = 1/(cosec x - cot x) ​
Anastasy [175]

Answer:

Sorry Bro

Step-by-step explanation:

I don't know the ans plzz donnot mind

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2 years ago
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Order 51.835, 51.836, 51.736, and 51.837 in decreasing order.
Tju [1.3M]

Answer:

<em><u>D.)</u></em>51.837, <em><u>B.)</u></em>51.836, <em><u>A.)</u></em>51.835, <em><u>C.)</u></em>51.736

Step-by-step explanation:

its decreasing in this order

3 0
3 years ago
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The edges of the diameter of a circle are at (-1,2) and (3,-1). Write the equation of the circle in general form.
Y_Kistochka [10]

Answer:

(x-1)²+ (y-0.5)²=6.25

Step-by-step explanation:

<u>The standard form of equation of a circle is;</u>

(x-a)²+(y-b)²=r² where (a,b) are the center of the circle and r is the radius

<u>Finding the mid-point of the given points</u>

(-1,2) and (3,-1)⇒midpoint will be 1/2(x₁+x₂) , 1/2(y₁+y₂)

midpoint= {1/2(-1+3), 1/2(2+-1)}

midpoint=(1,0.5)

<u>Finding the radius r; the distance from the center to either of the given two points</u>

Apply the distance formula d=√ (x₂-x₁)² +(y₂-y₁)²

Taking (x₁,y₁) as (1,0.5) and (x₂,y₂) as (-1,2) then

d=√ (-1-1)² +(2-0.5)²

d= √ (-2)²+(1.5)²

d=√4+2.25⇒√6.25⇒2.5

r=2.5

<u>Equation of the circle</u>

(x-1)² + (y-0.5)²=2.5²

(x-1)²+ (y-0.5)²=6.25

3 0
3 years ago
This for whoever wants to get 15 points for free.......Your welcome
Kobotan [32]

Answer:THANK YOUUUUUUU

Step-by-step explanation:

7 0
3 years ago
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Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the constant of the antid
vredina [299]

Answer:

6t + \frac{t^2}{2}+2/5t^{5/2} + C

Step-by-step explanation:

Given the expression;

g(t) = 6 + t + t²/√t

This can be rewritten as;

g(t) = 6 + t +t²/t^1/2

g(t) = 6 + t +t^{2-1/2}

g(t) = 6 + t +t^3/2

Integrate the result

\int\limits {(6 + t+t^{3/2}}) \, dt\\

Using the formula x^{n+1}/n+1

\int\limits {(6  + t+t^{3/2}}) \, dt\\ = 6t + \frac{t^2}{2}+\frac{t^{3/2+1}}{3/2 + 1} \\ = 6t + \frac{t^2}{2}+\frac{t^{5/2}}{5/2} \\= 6t + \frac{t^2}{2}+2/5t^{5/2} + C

5 0
3 years ago
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