1
Add the numbers
(
−
4
+
5
)
−
(
6
+
7
)
=
0
({\color{#c92786}{-4}}+{\color{#c92786}{5}})-(6+7)=xx^{0}
(−4+5)−(6+7)=xx0
(
1
)
−
(
6
+
7
)
=
0
({\color{#c92786}{1}})-(6+7)=xx^{0}
(1)−(6+7)=xx0
2
Add the numbers
1
−
(
6
+
7
)
=
0
1-({\color{#c92786}{6}}+{\color{#c92786}{7}})=xx^{0}
1−(6+7)=xx0
1
−
(
1
3
)
=
0
1-({\color{#c92786}{13}})=xx^{0}
1−(13)=xx0
3
Multiply the numbers
1
−
1
⋅
1
3
=
0
1{\color{#c92786}{-1}} \cdot {\color{#c92786}{13}}=xx^{0}
1−1⋅13=xx0
1
−
1
3
=
0
1{\color{#c92786}{-13}}=xx^{0}
1−13=xx0
4
Subtract the numbers
1
−
1
3
=
0
{\color{#c92786}{1-13}}=xx^{0}
1−13=xx0
−
1
2
=
0
{\color{#c92786}{-12}}=xx^{0}
−12=xx0
5
Combine exponents
−
1
2
=
0
-12={\color{#c92786}{xx^{0}}}
−12=xx0
−
1
2
=
1
-12={\color{#c92786}{x^{1}}}
−12=x1
Show less
Solution
−
1
2
=
1
Answer:
a1 = 0.5; common ratio = 5
Step-by-step explanation:
Let the common ratio = r
a2 = 2.5
a3 = 2.5r
a4 = 2.5r * r = 2.5r^2
We are told a4 = 62.5, so
2.5r^2 = 62.5
Divide both sides by 2.5
r^2 = 25
r = 5
a2 = a1 * r
a1 = a2/r = 2.5/5 = 0.5
Answer: a1 = 0.5; common ratio = 5
Answer:
The initial amount, A is approximately $19,991.1.
Step-by-step explanation:
The initial amount the man invests in the bank = A
The amount the man deposits after 15 years = $10,000
The amount in the account after 50 years = $251,894.21
The amount of money after every 15 years = 2 × Initial amount
Therefore, we have;
The amount in the account 15 years after when the man deposits another $10,000 = 2 × A
Therefore the initial amount at the 15th year = 2·A + 10000
The
We have;
2·A = A·(1 + r)¹⁵
(1 + r)¹⁵ = 2
1 + r = 2^(1/15)
r = 1 - 2^(1/15) = 0.04729412282
Therefore, we have;
On the 50th year, 50 - 15 = 35 year
$251,894.21 = (2·A + 10000)·(1 + 0.04729412282)³⁵
A = ($251,894.51/((1 + 0.04729412282)³⁵) - 10000)/2 ≈ $19991.1
The initial amount, A ≈ $19991.1.
If 60% out of the 2,660 students are males, then
40% out of t<span>he same 2,660 students are females
Ten the number of females is 40% x 2660 = 0.4 x 2660 = 1,064 females</span>
