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katrin [286]
3 years ago
6

Solve 6x – 17 = k for x.

Mathematics
2 answers:
mina [271]3 years ago
7 0
X= 23  im pretty sure hope this helps best of luck :)
Sergio [31]3 years ago
6 0

Answer: x=k+17/6

Step-by-step explanation: APEX

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explain step by step how to solve. please point out any similarities in the steps used for each question
Mamont248 [21]
#1
m∠A=180 - 115 - 24 = 41°

By the law of sines:

b/sinB = a/sinA  ⇒  
b = (a*sinB)/sinA = (21*sin24°)/sin41° = (21*0.4067)/0.656 ≈ 13

c/sinC = a/sinA  ⇒  
c = (a*sinC)/sinA = (21*sin115°)/sin41° = (21*0.9063)/0.656 ≈ 29


#2
m∠C=180 - 119 - 27 = 34°

By the law of sines:

b/sinB = a/sinA  ⇒  
b = (a*sinB)/sinA = (13*sin119°)/sin27° = (13*0.8746)/0.454 ≈ 25

c/sinC = a/sinA  ⇒  
c = (a*sinC)/sinA = (13*sin34°)/sin27° = (13*0.5592)/0.454 ≈ 16


#3
m∠C=180 - 57 - 37 = 86°

By the law of sines:

c/sinC = a/sinA  ⇒  
c = (a*sinC)/sinA = (11*sin86°)/sin57° = (11*0.9976)/0.8387 ≈ 13.1
6 0
3 years ago
Plzzzz help !!!! I need this done
STatiana [176]

Answer:

A) x + 2 ≤ 3

Step-by-step explanation:

To solve for this, you subtract 2 from both sides leaving you with:

x ≤ 1

which is what the graph is showing.

3 0
3 years ago
A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0
3 years ago
A lawyer spends $75.00 on 3 staplers and 3 pads of paper. If each stapler costs $21.75, and each pad of paper costs x dollars, w
PtichkaEL [24]
Each pad of paper cost 3.25. Here is how I found it.

21.75 x 3 = 65.25
75 - 65.25 = 9.75
9.75 / 3 = 3.25

X = 3.25

Is this what you were looking for?
6 0
2 years ago
Read 2 more answers
X² + 5<br> Given g(x) = 2x - 3,<br> 11,<br> x = 6<br> 2 &lt; x &lt; 6,<br> x &lt; 2<br> find g(5)
zvonat [6]

Step-by-step explanation:

uhm you know the excrotery system to the factor

5 0
3 years ago
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