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jenyasd209 [6]
3 years ago
9

Graph the Line y=4x−3

Mathematics
1 answer:
vladimir1956 [14]3 years ago
5 0
Do U have a picture???
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The area if a rectangle is 53.6cm^2.If the length is multiplied by four and the width is halved, the area would then be?
e-lub [12.9K]

Answer:

26.8cm²

Step-by-step explanation:

the area if a rectangle is 53.6cm^2.If the length is multiplied by four and the width is halved, the area would then be?​

Area of rectangle = length x width

53.6 = 4L x 1/2 W

53.6 = 2L × W

Divide both sides by 2

L × W = 53.6 ÷ 2

New area  = 26.8cm²

I hope this was helpful, please mark as brainliest

5 0
4 years ago
Making $40 payments each Friday,
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8 0
3 years ago
You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estim
pogonyaev

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36  

And rounded up we have that n=656

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by \alpha=1-0.80=0.20 and \alpha/2 =0.10. And the critical value would be given by:

z_{\alpha/2}=\pm 1.28

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

Since we don't have prior info for the proportion of interest we can use \hat p=0.5 as estimator. And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36  

And rounded up we have that n=656

5 0
3 years ago
The police department of a city with a population of 250000 wants to know how many residents wear their seatbelts regularly. whi
Alex Ar [27]
A 2500 you want the biggest sample size possible for more accurate results
4 0
3 years ago
Read 2 more answers
Iv)<br>6x+3y=6xy<br>2x + 4y= 5xy​
Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) =  (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5  - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0
3 years ago
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