All categories

3 years ago

Find the next two terms in the sequence. 7, 21, 63, 189, 315, 441 567, 1,701 378, 756 192, 195

1 answer:

8 0

<span>7, 21, 63, 189
7 x 3 = 21
21 x 3 = 63
63 x 3 = 189
189 x 3 = 567
567 x 3 = 1,701

Therefore, the nex two terms in the sequence are 567 and 1,701
</span>

You might be interested in

What is the following is the product of (-x - 7)(3x + 1)?

forsale [732]

Answer:

-3x^2-22x-7

Step-by-step explanation:

8 0

3 years ago

Find the Simple interest paid for eight years on a $850 loan at 7.5% a year

LekaFEV [45]

Answer:

850 divided by 7.5

Step-by-step explanation:

8 0

3 years ago

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

3 years ago

What are two solutions of 3 + 4 |x/2 + 3| = 11?

Alex

3 + 4abs(x/2 + 3) = 11 Subtract 3
4 abs(x/2 + 3) = 11 - 3
4 abs(x/2 + 3) = 8 Divide by 4
abs(x/2 + 3) = 8/4
abs(x/2 + 3) = 2

Solution 1
x/2 + 3 = 2 Subtract 3
x/2 = 2 - 3
x/2 = - 1 Multiply by 2
x/2 *2 = - 2
x = - 2

Solution 2
x/2 + 3 = - 2
x/2 = - 2 - 3
x/2 = - 5 Multiply by 2
x = -5 * 2
x = -10

Solutions
x = - 2 <<<< answer 1
x = -10 <<<< answer 2

3 0

4 years ago

Determine if the relation is a function if so state the domain and range

Sedaia [141]

Answer:

Function - Yes

Domain - [-3,0,3,4]

Range - [1,2,2,5]

Step-by-step explanation:

In a function, x-values cannot repeat and in this relation, x's do not repeat, therefore it is a function. The domain is the x-values on the graph from least to greatest; so to find the domain, simply take the first value of each coordinate and order them from least to greatest. Then, the range is the y-values, so to find the range take the second value from each coordinate and order them from least to greatest.

8 0

3 years ago