Answer:
See below
Step-by-step explanation:
Vertices are the black dots of the figure:
Point Q is at (1,4)
Point R is at (3,-2)
Point S is at (0,-1)
Point T is at (-2,2)
Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
So first thing is find the number of small boxes. Find 1% of 120, 1.2. Multiply 1.2 by 35, it’s 42.
Next find what the percent that 2/5 is. Divide two by five, it’s .4 or 40%. We already know one percent is 1.2 so multiply 1.2 by 40, 48.
Add this two.
42+48=90.
120-90=30
Small boxes:42
Medium boxes: 48
Large:30
42*6=252
48*10=480
15*30=450
1182 eggs total.
Set up multiplication/division of ratios to cancel out units you don't need for the final answer and introduce those that you do.
We have m/s and we want m/min so
(100m/s)(60s/min)=6000m/min
Answer: 2cm
Step-by-step explanation:
