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4 years ago

Please help me asap

Mathematics

2 answers:

8_murik_8 [283]4 years ago

7 0

1.) >
2.) is the fourth choice
3.) is 120

timurjin [86]4 years ago

5 0

1.>
2.4with exponent of 6 aka (D)
3.120

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jek_recluse [69]

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3 years ago

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hammer [34]

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3 years ago

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First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

What is the GCF of 11ab + 32ab ?

Diano4ka-milaya [45]

The GCF is of 11ab +32ab is 43ab

6 0

3 years ago

Find the equation of the line with m=6 and b = -7. Write the equation in slope intercept form.

Harman [31]

Answer: $y=6x-7$

Step-by-step explanation:

We use the formula y=mx+b to put it into slope-intercept form

m=6 (slope)

b=-7 (y-intercept)

Therefore, the answer is y=6x-7

4 0

3 years ago

Please help me asap​

Please help me asap