Answer: The diagrams above show an area that <u>was once a pasture</u> that has since undergone changes to the <u>vegetation </u>over time.
The following changes in the <u>hydrologic cycle</u> is most likely to occur as a result of the change in vegetation in the area:
Explanation:
When we <em>lose vegetation</em> in an area we face serious problems, one of them is the decreased precipitation . If changes are <em>made by man</em>, for example, as in deforestation, the consequences are <u>even worse.</u>
<u><em>Deforestation </em></u>can cause a serious <u>reduction of rainfall</u> in the tropics, with serious consequences for the population not only in that region but in <em>neighboring areas.</em> The air that passes over large areas of tropical forest produces at least twice as much rain as that which travels over areas of low vegetation .
In turn this also <u>affects the other factors</u> of the cycle. The vegetation <em>contributes</em> moisture through an <em>evapotranspiration process</em>, as it is called the evaporation of the rivers together with the transpiration of the plants. This moisture is transported by the winds.
We can say then that <u><em>the loss of vegetation</em></u> in an area (whether on purpose or not) <u><em>will corrupt several cycle factors</em></u>, mainly damaging the rainfall rate.
C.Halite is the correct answer these are formed by the evaporation of seawater and the salt remaining to help the rock to form.
Hope this helps!
Answer:
nucleotide
.
Explanation:
The monomer that contains a base, sugar and phosphate group is a nucleotide.
D, correct me if i’m wrong
Answer:
The correct answer is 160.
Explanation:
Based on the given question, the total number of fruit flies is 1000, of which red eye flies are 640. Thus, the number of sepia eye flies will be 1000-640 = 360.
On the basis of the Hardy-Weinberg equation, p+q = 1, in which p is the rate of recurrence of one allele, that is, dominant and q is the rate of recurrence of the other allele, that is, recessive.
q^2 for the population is 360/1000 = 0.36, q = 0.6.
Therefore, p = 1-q = 1-0.6 = 0.4.
The frequency of homozygous dominant allele is denoted by p^2 = 0.16.
Hence, the number of homozygous dominant for red eye color would be 16% of 1000 which will be equal to 160.
