The answer is 144
hope this helped!
Answer:
Let f_n be the number of rabbit pairs at the beginning of each month. We start with one pair, that is f_1 = 1. After one month the rabbits still do not produce a new pair, which means f_2 = 1. After two months a new born pair appears, that is f_3 = 2, and so on. Let now n 
3 be any natural number. We have that f_n is equal to the previous amount of pairs f_n-1 plus the amount of new born pairs. The last amount is f_n-2, since any two month younger pair produced its first baby pair. Finally we have
f_1 = f_2 = 1,f_n = f_n-1 + f_n-2 for any natural n 3.
Answer:
42,183
Step-by-step explanation:
We will use the Continuous Compounding Interest since a regular interval was not stated.
P(t) = Pe^(rt)
We will plug in the variables to the formula
P(t) = 31250 * e^(.12 * 2.5)
We can simplify and evaluate the compound interest.
P(t) = 42183.08
Answer:
a) 0.2347, 0.0007
b) 1.30
c) 0.63
Step-by-step explanation:
Given –
Mean = 73.4
Sigma = 4.7
Probability that the speed is greater than 70 is
P (X>70) = P (z> (70-73.4)/4.7) = P (z>-0.72) = 0.7653
a) The probability that a car is not speeding = 1 - 0.7653 = 0.2347
The probability that all 5 cars are not speeding = (0.2347)5 = 0.0007
b) E (X) = 1/p = 1/0.7653 = 1.30
c) Standard deviation = Sqrt (1-p/p) = (1-0.7653)/0.7653 = 0.63
Answer:
can you plz send the full image
