V+w=7<br> v+W=1<br> Find the rise over run

[ 64 (-8) ] (-2) help it’s for my quiz

Lana71 [14]

$(64 \times ( - 8)) \times ( - 2)$

$( - 512) \times ( - 2)$

$1024$

Therefore, the answer is <u>1</u><u>0</u><u>2</u><u>4</u><u>.</u>

<h3><em>Benjemin</em></h3>

3 0

3 years ago

A metal beam was brought from the outside cold into a machine shop where the temperature was held at 65degreesF. After 5 min, t

ivolga24 [154]

Answer:

The beam initial temperature is 5 °F.

Step-by-step explanation:

If T(t) is the temperature of the beam after t minutes, then we know, by Newton’s Law of Cooling, that

$T(t)=T_a+(T_0-T_a)e^{-kt}$

where $T_a$ is the ambient temperature, $T_0$ is the initial temperature, $t$ is the time and $k$ is a constant yet to be determined.

The goal is to determine the initial temperature of the beam, which is to say $T_0$

We know that the ambient temperature is $T_a=65$ , so

$T(t)=65+(T_0-65)e^{-kt}$

We also know that when $t=5 \:min$ the temperature is $T(5)=35$ and when $t=10 \:min$ the temperature is $T(10)=50$ which gives:

$T(5)=65+(T_0-65)e^{k5}\\35=65+(T_0-65)e^{-k5}$

$T(10)=65+(T_0-65)e^{k10}\\50=65+(T_0-65)e^{-k10}$

Rearranging,

$35=65+(T_0-65)e^{-k5}\\35-65=(T_0-65)e^{-k5}\\-30=(T_0-65)e^{-k5}$

$50=65+(T_0-65)e^{-k10}\\50-65=(T_0-65)e^{-k10}\\-15=(T_0-65)e^{-k10}$

If we divide these two equations we get

$\frac{-30}{-15}=\frac{(T_0-65)e^{-k5}}{(T_0-65)e^{-k10}}$

$\frac{-30}{-15}=\frac{e^{-k5}}{e^{-k10}}\\2=e^{5k}\\\ln \left(2\right)=\ln \left(e^{5k}\right)\\\ln \left(2\right)=5k\ln \left(e\right)\\\ln \left(2\right)=5k\\k=\frac{\ln \left(2\right)}{5}$

Now, that we know the value of $k$ we can use it to find the initial temperature of the beam,

$35=65+(T_0-65)e^{-(\frac{\ln \left(2\right)}{5})5}\\\\65+\left(T_0-65\right)e^{-\left(\frac{\ln \left(2\right)}{5}\right)\cdot \:5}=35\\\\65+\frac{T_0-65}{e^{\ln \left(2\right)}}=35\\\\\frac{T_0-65}{e^{\ln \left(2\right)}}=-30\\\\\frac{\left(T_0-65\right)e^{\ln \left(2\right)}}{e^{\ln \left(2\right)}}=\left(-30\right)e^{\ln \left(2\right)}\\\\T_0=5$

so the beam started out at 5 °F.

6 0

3 years ago

Jacob throws an acorn into the air. It lands in front of him. The acorn's path is

Burka [1]

Answer:

hits the ground at x = -0.732, and x = 2.732
only the positive solution is reasonable

Step-by-step explanation:

The acorn will hit the ground where the value of x is such that y=0. We can find these values of x by solving the quadratic using any of several means.

__

<h3>graphing</h3>

The attachment shows a graphing calculator solution to the equation

-3x^2 + 6x + 6 = 0

The values of x are -0.732 and 2.732. The negative value is the point where the acorn would have originated from if its parabolic path were extrapolated backward in time. Only the positive horizontal distance is a reasonable solution.

__

<h3>completing the square</h3>

We can also solve the equation algebraically. One of the simplest methods is "completing the square."

-3x^2 +6x +6 = 0

x^2 -2x = 2 . . . . . . . . divide by -3 and add 2

x^2 -2x +1 = 2 +1 . . . . add 1 to complete the square

(x -1)^2 = 3 . . . . . . . . written as a square

x -1 = ±√3 . . . . . . . take the square root

x = 1 ±√3 . . . . . . . add 1; where the acorn hits the ground

The numerical values of these solutions are approximately ...

x ≈ {-0.732, 2.732}

The solutions to the equation say the acorn hits the ground at a distance of -0.732 behind Jacob, and at a distance of 2.732 in front of Jacob. The "behind" distance represents and extrapolation of the acorn's path backward in time before Jacob threw it. Only the positive solution is reasonable.

3 0

2 years ago

Read 2 more answers

Tareq pays $22.10 for 2.6 pounds of salmon. What is the price per pound of the salmon? *

e-lub [12.9K]

Answer:

8.50

Step-by-step explanation:

Divide $22.10 over 2.6 pounds of salmon

6 0

3 years ago

Read 2 more answers

For home economics class, Sandra has 5 cups of flour. She made 3 batches of cookies that each used 1.5 cups of flour. Write and

stealth61 [152]

Because one batch of cookies uses up 1.5 cups of flour, we can write this as:

batch of cookies = 1.5 cups of flour

Because she made 3 batches we can say:

batch of cookies = 1.5 cup of flour * 3 (because she has made three)

This equals to 3 batches of cookies using up 4.5 cups of flour.

Because at the beginning she had 5 cups and she has used 4.5 cups of flour for making the batches of cookies, she is left with 0.5 cups of flour:

5 cups at the start - 4.5 cups used for cooking = 0.5 cups in the end.

8 0

3 years ago

Read 2 more answers

V+w=7 v+W=1 Find the rise over run