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solong [7]
4 years ago
6

What is the first step in solving 5x-3=12?

Mathematics
2 answers:
sergij07 [2.7K]4 years ago
6 0

Answer: 5x = 12 + 3

5x = 15 (divide both sides by 5 to get x)

Step-by-step explanation:

5x/5 = 15/5\\x = 3

Lena [83]4 years ago
3 0

Answer:

X = 3

Step-by-step explanation:

5X - 3 = 12

add 3 to both sides of the equal sign

5X = 15

divide 5 to both sides of the equal sign

X = 3

MARK ME BRAINLIEST

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If f(x) = ||x|| , find f (-1/4)
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How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

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4 years ago
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7 0
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Solve.
horrorfan [7]

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To solve for x multiply both sides by 2:

x = -1.46

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2 years ago
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