The domain of the ellipse is [-4. 6] and the range of the ellipse is [-4. 0]
<h3>How to determine the domain and the range of the ellipse?</h3>
The equation of the ellipse is given as:
4x^2 + 25y^2 – 8x + 100y + 4 = 0
Next, we plot the graph of the ellipse
See attachment for the graph of the ellipse
<u>The domain</u>
From the attached graph the minimum and the maximum values of x are:
Minimum = -4
Maximum = 6
So, the domain of the ellipse is [-4. 6]
<u>The range</u>
From the attached graph the minimum and the maximum values of y are:
Minimum = -4
Maximum = 0
So, the range of the ellipse is [-4. 0]
Hence the domain of the ellipse is [-4. 6] and the range of the ellipse is [-4. 0]
Read more about domain and range at:
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X^4 + 8x^3 - 2x^2 - 4x - 4. I just thought of it like the second polynomial plus the polynomial you need to solve for equals the first polynomial.
Cos(17pi/8)
cos(17π/8)
But π radians = 180°
17π/8 radians = (17/8) * 180 = 382.5
But this is more than 360°, so we have the basic angle by subtracting 360°
382.5 - 360 = 22.5
cos(17π/8) = Cos22.5
Recall double angle formula for cos.
cos2θ = 2cos²θ - 1
Therefore
cos(2*22.5) = 2cos²(22.5) - 1
cos45 = 2cos²(22.5) - 1
(√2)/2 = 2cos²(22.5) - 1
2cos²(22.5) - 1 = (√2)/2
2cos²(22.5) = (√2)/2 + 1
2cos²(22.5) = (2 + √2) / 2
cos²(22.5) = (2 + √2) / 4
cos22.5 = √( (2 + √2)/4) ................(note)
cos22.5 = √(2 + √2) / 2
Option (a) seems like the closest, comparing to (note) above.
Answer:
add the 11 to both sides to cancel it out.
Step-by-step explanation:
so basically
5x - 11 + 11 = 42 +11
5x = 53
