The domain is t=0 to t=3.2 and range is y = 0 to 57.125 feet.
<u>What are Domain and range of a Function?</u>
- The range of values that we are permitted to enter into our function is known as the domain of a function.
- The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input.
- After we enter an x value, the function outputs this sequence of values. The y values are those.
- A function can be compared to a piece of equipment on an assembly line.
- A few screws and nuts are located on one end of the assembly line, while a car is located on the other. The function is the device in the center. The domain is the screws and bolts that we insert into the machine. The car at the other can be thought of as the range.
Given function is : y = -16t^2 + 50t + 4
It hits the ground when y=0
0 = -16t^2 + 50t + 4
8t^2 -25t -2 = 0
t = 25/16 + (1/16)sqrt(625+64) = (25+26.25)/16 = 51.25/16 = 3.2 seconds
domain is t=0 to t=3.2 [3.2]
take the derivative and set it equal to zero to find maximum height
-32t +50 = 0
t = 50/32 = 25/16 = 1.5625 seconds
-16(25/16) + 50(25/16) + 4 = 34(25/16) + 64/16 = (17(25)+32)/8 = 57.125 = maximum height
range is y = 0 to 57.125 feet. the discus goes from 4 feet to 57 1/8 feet and back down to 0 feet.
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Answer: 135cm
Step-by-step explanation
Volume of a cylinder = πr²h
Volume of a cone. = 1/3πr²h
The two shapes are both solid shapes.
Since the have same volume, we can then equate the two together and solve for the height of the cone.
Now make H the height and R the radius of the cylinder and h the height and r the radius of the cylinder.
Now equating the two
πR²H = 1/3πr²h
Now substitute for the values now
Multiply through by 3
3πR²H = πr²h
But π is common so it could be obliterated from the equation
3R²H = r²h
3 x 12² x 20 = 8² x h
3 x 144 x 20 = 64 x h
60 x 144 = 64h
8640. = 64h
Therefore
h = 8640/64
= 135cm
I have geometry to but i didn’t get to that yet sorry
Answer:
Squirrel population is 440 squirrels.
Step-by-step explanation:
It is given that there are 22 squirrels are marked.
Later the company returned and counted a total of 220 squirrels of which are marked were 11.
So, we can set up proportional equation to find the squirrel population.
Let squirrel population is x.
We can set up proportional equation as

Cross multiply
11 x=4840
Divide both sides by 11
x=440
Best estimate is 440.