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Elena-2011 [213]
3 years ago
14

Write the equation of a line that is parallel to y=0.6x+3 and that passes through the point

Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0
A line parallel to y = 0.6x + 3 will be of the form:

y = 0.6x + k

where k is a constant.

It passes through (-3,-5)

Thus,

y = 0.6x + k \\ \\ -5 = 0.6 \times (-3) + k \\ \\ -5 = -1.8 + k \\ \\k = -5 + 1.8 \\ \\ k = -3.2

\textbf{The equation is \: \: y = 0.6x - 3.2}
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