All categories

2 years ago

What is -(c-4)=5?so what is 'c'

Mathematics

2 answers:

alexgriva [62]2 years ago

6 0

-(c-4)=5
c-4=-5
c=-1

Check answer:
-(-1-4)=5
-(-5)=5
5=5

Yanka [14]2 years ago

5 0

$-(c-4)=5 \\ \\ -c + 4 = 5 \\ \\ 4 - c = 5 \\ \\ -c = 5 - 4 \\ \\ -c = 1 \\ \\ c = -1 \\ \\$

The final result is: c = -1.

You might be interested in

A pharmaceutical company prefers experimental studies to conducting surveys or observational studies. what is most likely the re

never [62]

Pharmaceutical companies prefers experimental studies to conducting surveys and observational studies because companies can manipulate or suggest methods easily to have good outcomes and they are able to directly observe the results. Experimental studies is a type of study in which a procedure and method is intentionally introduced.

8 0

2 years ago

Read 2 more answers

Will give barinliest. I need help Now.

Aloiza [94]

Answer:

im pretty sure its N = w^2 + 2w

hope this helps if it does plz brainliest :)

Step-by-step explanation:

4 0

2 years ago

Tate fills a container with 9 1/2 cups of lemonade. Tate drinks 32 fl. oz. of lemonade. How many fluid ounces are left?

iren [92.7K]

Answer:

44 fluid ounces of lemonade are left.

Step-by-step explanation:

Given:

Tate fills a container with 9 1/2 cups of lemonade.

Tate drinks 32 fl. oz. of lemonade.

Now, to find the quantity of fluid ounces left.

So, we convert the unit of cups into fluid ounces.

Tate fill the container of lemonade with = $9\frac{1}{2}\ cups.$

As, 1 cup = 8 fluid ounces.

So, by conversion factor:

$9\frac{1}{2} \times 8$

$=\frac{19}{2} \times 8$

$=9.5\times 8=76\ fl.\ oz.$

Thus, Tate fill the container of lemonade with = 76 fl. oz.

Tate drinks lemonade = 32 fl. oz.

Now, to get the fluid ounces left we subtract the quantity of lemonade Tate drink from the total quantity of lemonade filled in the container:

$76-32$

$=44\ fl.\ oz.$

Therefore, 44 fluid ounces of lemonade are left.

3 0

2 years ago

(1) (10 points) Find the characteristic polynomial of A (2) (5 points) Find all eigenvalues of A. You are allowed to use your ca

Yuri [45]

Answer:

Step-by-step explanation:

Since this question is lacking the matrix A, we will solve the question with the matrix

$\left[\begin{matrix}4 & -2 \\ 1 & 1 \end{matrix}\right]$

so we can illustrate how to solve the problem step by step.

a) The characteristic polynomial is defined by the equation $det(A-\lambdaI)=0$ where I is the identity matrix of appropiate size and lambda is a variable to be solved. In our case,

$\left|\left[\begin{matrix}4-\lamda & -2 \\ 1 & 1-\lambda \end{matrix}\right]\right|= 0 = (4-\lambda)(1-\lambda)+2 = \lambda^2-5\lambda+4+2 = \lambda^2-5\lambda+6$

So the characteristic polynomial is $\lambda^2-5\lambda+6=0$ .

b) The eigenvalues of the matrix are the roots of the characteristic polynomial. Note that

$\lambda^2-5\lambda+6=(\lambda-3)(\lambda-2) =0$

So $\lambda=3, \lambda=2$

c) To find the bases of each eigenspace, we replace the value of lambda and solve the homogeneus system(equalized to zero) of the resultant matrix. We will illustrate the process with one eigen value and the other one is left as an exercise.

If $\lambda=3$ we get the following matrix

$\left[\begin{matrix}1 & -2 \\ 1 & -2 \end{matrix}\right]$ .

Since both rows are equal, we have the equation

$x-2y=0$ . Thus x=2y. In this case, we get to choose y freely, so let's take y=1. Then x=2. So, the eigenvector that is a base for the eigenspace associated to the eigenvalue 3 is the vector (2,1)

For the case $\lambda=2$ , using the same process, we get the vector (1,1).

d) By definition, to diagonalize a matrix A is to find a diagonal matrix D and a matrix P such that $A=PDP^{-1}$ . We can construct matrix D and P by choosing the eigenvalues as the diagonal of matrix D. So, if we pick the eigen value 3 in the first column of D, we must put the correspondent eigenvector (2,1) in the first column of P. In this case, the matrices that we get are

$P=\left[\begin{matrix}2&1 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}3&0 \\ 0 & 2 \end{matrix}\right]$

This matrices are not unique, since they depend on the order in which we arrange the eigenvalues in the matrix D. Another pair or matrices that diagonalize A is

$P=\left[\begin{matrix}1&2 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}2&0 \\ 0 & 3 \end{matrix}\right]$

which is obtained by interchanging the eigenvalues on the diagonal and their respective eigenvectors

4 0

2 years ago

Write the coordinate of the intercept

Basile [38]

Answer:

m = 2/3

y-intercept: 2

Explanation:

First convert this equation into standard form by distributing the 6y and -4x from the coefficient of 2, and then putting the variables in order.

This equation should be in the form: Ax + By = C (Standard form)

y = -Ax/B + C/B : y = mx + b (Slope intercept form)

2(6y - 4x) = 24 → 12y - 8x = 24

→ -8x + 12y = 24 → -8x = -12y + 24 → 8x = 12y - 24 → 8x - 12y = -24

8x - 12y = -24

| | |

A B C

Once you have standard form, you are ready to convert this into slope intercept by isolating the y completely.

8x - 12y = -24

-8x -8x

(First through the subtraction property of equality, remove 8x from both sides so that -12y is by itself on the left)

-12y = -8x - 24

×-1 ×-1 ×-1

(Through the identity property of negative 1, remove the negative sign from all of the numbers because a negative times a negative is a positive)

12y = 8x + 24

(Lastly, through the division property of equality, divide all sides by 12 because it is the coefficient of y, which will solve for the variable)

8 0

2 years ago