29/50 or 0.58 is the answer
Answer:
Step-by-step explanation:
Slope-intercept form: y = mx + b
The line intersect Y-axis at y=0 so b = 0
The line passses through points (0, 0) and (2, -1), so the slope:
Therefore the equation:
<u><em>Answer:</em></u>
<u><em>Step-by-step explanation:</em></u>
<u><em>Please give me brainliest.</em></u>
Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
Answer:
Step-by-step explanation:
answer : C when this graph passes trough x-axis
