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4 years ago

1. What is the arithmetic mean of the numbers 14,16,18,5,17 ?

Mathematics

2 answers:

Basile [38]4 years ago

5 0

Number 2 is 20 number 3 is 11

kipiarov [429]4 years ago

4 0

Number 2 is 20 number 3 is 11

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Evaluate the expression when x = 8 and y = 1.

timama [110]

The answer is b. Hope this helped

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3 years ago

Read 2 more answers

What’s a solution set

solong [7]

It's the group of correct solutions to a given problem.

Imagine you have apples, pears and peaches you're asked <em>"what fruits do you have"</em>? Your solution set would be {apple, pear, peach}.

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3 years ago

Determine whether the following function is one-to-one. f ( x ) = 6 x + 1

seraphim [82]

Answer:

one to one function

Step-by-step explanation:

f(x)=6x+1 can only be a one to one function when x1=x2

Now,

f(x1)=f(x2)

or, 6x1 + 1 = 6x2 + 1

or, 6x1 = 6x2

or, x1 = x2

So f(x)= 6x + 1 is a one to one function

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3 years ago

Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr

Sonja [21]

Answer:

Step-by-step explanation:

Given that;

Compressed Soil 2.85 2.66 3 2.82 2.76 2.81 2.78 3.08 2.94 2.86 3.08 2.82 2.78 2.98 3.00 2.78 2.96 2.90 3.18 3.16

Intermediate Soil 3.17 3.37 3.1 3.40 3.38 3.14 3.18 3.26 2.96 3.02 3.54 3.36 3.18 3.12 3.86 2.92 3.46 3.44 3.62 4.26

Compressed soil intermediate soil

Mean 2.907 3.286

SD 0.1414 0.2377

Here we have,

$\bar x_1 =3.286\\ \bar x_2 =2.907\\s_1 =0.2377\\ s_2 =0.1414\\n_1=19\\n_2=20$

The pooled Standard deviation

$s_p=\sqrt{\frac{(n_1-1)s_1^2(n_2-1)s_2^2}{n_1+n_2-2} } \\\\=0.1943$

So standard error for difference in population mean is

$s_{\bar x_1 - \bar x_2} = \sqrt{\frac{s_p^2}{n_1}+\frac{s_p^2}{n_2} } \\\\=0.0623$

by inputting the values we get 0.0623

Degree of freedom for t is

df = 19 + 20 - 2 = 37,

so t-critical value is 2.715.

So required confidence interval for

$\mu_{1} - \mu_{2}$ will be

$( \bar x_1 - \bar x_2) \pm t_{critical}*s_{\bar x_1 - \bar x_2}$

$=0.3793 \pm2.715*0.063\\\\=0.3793\pm0.1690$

So required confidence interval is (0.2103 , 0.5483).

6 0

3 years ago

Find the product of 2(5.9) mentally using the distributive property.

VARVARA [1.3K]

2(5.9) is 11.8

Hopefully i is right I did this in my head.

7 0

3 years ago