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2 years ago

Given cos(x)=1/2, what is the value of cos(x+pi)?

Mathematics

1 answer:

patriot [66]2 years ago

8 0

Answer:

-1/2

Step-by-step explanation:

cos(x+pi) = -cos(x), so the answer is -1/2.

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Y = 2x – 15<br> y = 5x<br> Can anyone tell me the steps how to solve this and the answer

Brilliant_brown [7]

Use substitution
Plug in 5x for y
5x = 2x - 15
Subtract 2x
3x = -15
Divide by 3
x = -5, y = -25
Solution: (-5, -25)

5 0

3 years ago

Factor completely. 10x^3 + 2x^2 + 5x + 1

jonny [76]

Answer:

(5x + 1)x(2x^2+1)

Step-by-step explanation:

6 0

3 years ago

Find the length of the hypotenuse of a 45°-45°-90° triangle with a leg<br> length of 8 centimeters.

MArishka [77]

Answer:

8 $\sqrt{2$ = $\sqrt{128$ = 11.31

Step-by-step explanation:

3 0

3 years ago

In a book the characters are trying to determine whether the Poisson probabilistic model can be used to describe the locations t

oksian1 [2.3K]

Answer:

The estimated mean number of rockets hits in the region is 533.

Step-by-step explanation:

We are given the following information,

Number of rocket hits | Observed number of regions

0 | 228

1 | 214

2 | 94

3 | 32

4 | 7

5 | 0

6 | 0

7 | 1

We are asked to estimate the mean number of rocket hits in the region.

The mean or expected value is given by

$\mu = \sum (x \cdot P(x)) \\\\\mu = (0 \cdot 228) + (1 \cdot 214) + (2 \cdot 94) + (3 \cdot 32) + (4 \cdot 7) + (5 \cdot 0) + (6 \cdot 0) + (7 \cdot 1) \\\\\mu = 0 + 214 +188+ 96 +28 +0+ 0 + 7 \\\\\mu = 533$

Therefore, the mean number of rockets hits in the region is 533.

5 0

3 years ago

Need help on this one

ivolga24 [154]

If a triangle has side lengths 5, 5, and 8, then the triangle should be classified as isosceles.

This is because an isosceles triangle has two sides of the same length and one side of a different length. This isn’t an equilateral triangle (where all sides are of equal length) or a scalene triangle (where all sides are of different lengths).

Hope this helps!

8 0

3 years ago