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3 years ago

What is another way to write the ratio 13:6

Mathematics

2 answers:

NARA [144]3 years ago

7 0

Answer:

13/6

Step-by-step explanation:

it can also be written as a fraction

Rzqust [24]3 years ago

5 0

Answer:

13/6

Step-by-step explanation:

It can be written in fraction form, with the semicolon, and one other way

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What is the length of BC¯¯¯¯¯ ? Enter your answer in the box. units Triangle A B C with horizontal side B C. Vertex A lies above

OlgaM077 [116]

Answer: The length of BC is 22 units.

Explanation:

It is given that the Triangle ABC with horizontal side BC. Vertex A lies above side BC. Angle B and angle C are marked congruent. The length of side AC is labeled as 2x-24. The length of side AB is labeled as x-2. The length of side B C is labeled as x.

If two angles of a triangle are same it means the triangle is an isosceles triangle.

Since the angle B and C are congruent therefore the lines AB and AC are same.

$2x-24=x-2$

$2x-x=-2+24$

$x=22$

Since the side BC=x therefore the measure of BC is 22 units.

7 0

3 years ago

Which answer explains one way that the length of this line segment can be determined?

jarptica [38.1K]

Subtract 4 and 1
4-1=3
distance or length of this line segment is 3

7 0

4 years ago

Read 2 more answers

Is a triangle whose side measure 12 ft, 16 ft and 20 ft a right triangle?

tensa zangetsu [6.8K]

Answer:

This is a Right Triangle

Step-by-step explanation:

12=a 16=b 20=c

Now lets solve

a^2+b^2=c^2

144+b^2=c^2

144+256=c^2

144+256=400

c^2=400

The square root of 400 is 20..

This IS a Right Triangle

7 0

3 years ago

Solve for m.<br> m/9 + 2/3 =7/3

Nuetrik [128]

Answer:

m= 15

Step-by-step explanation:

$\frac{m}{9} + \frac{2}{3} = \frac{7}{3}$

To solve for m, start by moving the constants (numbers that are not attached to any variable) to the other side of the equation.

$\frac{m}{9} = \frac{7}{3} - \frac{2}{3}$

Simplify:

$\frac{m}{9} = \frac{5}{3}$

Multiply both sides by 9:

$m = \frac{5}{3} \times 9$

Crossing out 3 from the denominator and from 9:

m= 5(3)

m= 15

8 0

2 years ago

A piece of wire of length L will be cut into two pieces, one piece to form a square and the other piece to form an equilateral t

inn [45]

Answer:

(a) square: L; triangle: 0.

(b) square: L·(-16+12√3)/11; triangle: L·(27-12√3)/11

Step-by-step explanation:

<u>Strategy</u>: First we will write each area in terms of its perimeter. Then we will find the total area in terms of the amount devoted to the square. Differentiating will give a way to find the minimum total area.

In terms of its perimeter p, the area of a square is ...

A_square = p^2/16

In terms of its perimeter p, the area of an equilateral triangle is ...

A_triangle = p^2/(12√3)

Then the total area of the two figures whose total perimeter is L with "x" devoted to the square is ...

A_total = x^2/16 + (L-x)^2/(12√3)

(a) We know when polygons are regular, the one with the most area for the least perimeter is the one with the most sides. Hence, the total area is maximized when all of the wire is devoted to the square.

(b) The derivative of A_total with respect to x is ...

dA/dx = x/8 -(L-x)/(6√3)

This will be zero when ...

x/8 = (L-x)/(6√3)

x(6√3) = 8L -8x

x(8 +6√3) = 8L

x = L·8/(6√3 +8) = 8L(6√3 -8)/(64-108)

x = L·(12√3 -16)/11

The total area is minimized when L·(12√3 -16)/11 is devoted to the square, and the balance is devoted to the triangle.

5 0

3 years ago