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4 years ago

Simplify. 0.55−(0.9−0.8)⋅4

Mathematics

2 answers:

Alisiya [41]4 years ago

7 0

0.55−(0.9−0.8)⋅4
=0.55 − 3.6 + 3.2
= 0.15

Valentin [98]4 years ago

4 0

Answer:

0.15

Step-by-step explanation:

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A specific brand of gourmet chocolate candy contains 7.00 gg of dietary fat in each 22.7-gg piece. How many kilograms of dietary

Oduvanchick [21]

Answer:

635599482kg

Step-by-step explanation:

A gourmet chocolate candy has 7.00 gg of dietary fat in each 22.7-gg piece

for the 22.7 piece , the gg is 7 x 22.7 = 158.9gg in total

1gg = 2204622.6218488 lbs

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for the box of 4.00 lblb of candy

it is 350314534.612 x 4 = 1401258138.45lb

since our answer is needed in kilograms we convert 1401258138.45lb to kilograms

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4 years ago

Find the value of n -2(4 + 2n)= -20

Mamont248 [21]

Answer:

n= -3

-2(4+2n) = - 20

-8+4n = -20

4n = -20+8

4n = -12

divide both sides by 4

8 0

3 years ago

Solve. High school pre-cal

Oliga [24]

Answer:

Answer: Quadrant 4

Step-by-step explanation:

Graph of Functions

Let's analyze the function

$\displaystyle y=\frac{x^2+3x}{x+1}$

To better understand the following analysis, we'll factor y

$\displaystyle y=\frac{x(x+3)}{x+1}$

For y to have points in the first quadrant, at least one positive value of x must produce one positive value of y. It's evident that any x greater than 0 will do. For example, x=1 will make y to be positive in the numerator and in the denominator, so it's positive

For y to have points in the second quadrant, at least one negative value of x must produce one positive value of y. We need two of the factors that are negative. It can be seen that x=-2 will make y as positive, going through the second quadrant.

For the third quadrant, we have to find at least one value of x who produces a negative value of y. We only need to pick a value of x that makes one or all the factors be negative. For example, x=-4 produces a negative value of y, so it goes through the third quadrant

Finally, the fourth quadrant is never reached by any branch because no positive value of x can produce a negative value of y.

Answer: Quadrant 4

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4 years ago

Given B(17,5), C(11, -3), D-1, 2), and E(x, -6), find the value of x so that BC || DE.

son4ous [18]

Answer:

$x=-7$

Step-by-step explanation:

Remember that:

Two lines are parallel if their slopes are the same.
Two lines are perpendicular if their slopes are negative reciprocals.
And two lines are neither (a.k.a intersecting) if they are neither parallel nor perpendicular.

We want to find the value of x such that $\overline{BC}\parallel\overline{DE}$ .