Answer:
The answer to your question is: (3x + 5)(9x² - 15x + 25)
Step-by-step explanation:
Data
G(x) = 27x³ + 125
This is a sum of cubes
Process
![\sqrt[3]{27} = 3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%20%3D%203)
![\sqrt[3]{125} = 5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D%205)
27x³ + 125 = (3x)³ + (5)³ = (3x + 5)(9x² - 15x + 25)
Answer:
32.33 <= m
Step-by-step explanation:
Since we are dealing with below sea level our initial starting point and max level will both be negative values, while our descending rate will also be negative because we are going down. Using the values provided we can create the following inequality...
-400 <= -12m - 12
Now we can solve the inequality to find the max number of minutes that the submarine can descend.
-400 <= -12m - 12 ... add 12 on both sides
-388 <= -12m ... divide both sides by -12
32.33 <= m
Area = π r²
area of the required sector = (80/360) π * 15²
≈ 157.08
We are taking one quarter of the 2/5 of the students who play sports.
one quarter of 2/5 is 2/20 or 1/10.
