Answer:
9
Step-by-step explanation:
I used tan but there's probably an easier way to do this but 4*tan(20)=8.94 then round it up to 9
Answer:
0.281 ; 0.864
Step-by-step explanation:
1.)
p decreases as n increases (n increases, p--> 0)
λ ≥ 0
P(x = x) = (e^-λ * λ^x) ÷ x!
λ for Ford = 1.27
B) zero problems :
P(x = 0) :
(e^-1.27 * 1.27^0) ÷ 0! = 0.281
P(x = 0) = 0.281
Two or fewer problems :
P(x ≤ 2) = p(x = 0) + p(x = 1) + p(x = 2)
P(x ≤ 2) = 0.281 + 0.357 + 0.226
P(x ≤ 2) = 0.864
D.) It allows for early detection and thus adequate curtailment of the problem at an a stage in which it seems easier to curb.
Answer:
(6^-4)^-4, (6^-2)^-8, (6^8)^2
2x-5= 7
Add 5 on both sides
2x= 12
Divide by 2
X= 6