If the volume of this box was 750 inches what would the value of the hieght have to be

The Baker family is traveling a total of 1,045 miles from their home to Florida for a summer vacation. They traveled 409 miles o

alexdok [17]

Answer: A. 397 miles

Step-by-step explanation:

Add the miles traveled on Saturday and Sunday to find out how many miles were traveled in total.

409 + 239 = 648

Now, subtract the total number of miles traveled from the original distance.

1,045 - 648 = 397

5 0

3 years ago

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For the following figure, complete the statement for the specified points.

AVprozaik [17]

The correct answer is coplanar

EXPLANATION

Coplanar means the three points A , B and Q are on the same plane.

They are not colinear, because they are not in a straight line. It is only A and Q that are on the same straight line. If B had fallen in line with them, the three points would have been collinear as well.

4 0

3 years ago

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Farah made 28 out of 84 shots on a goal in a recent hockey season. Write her shots made out of shots attempted as a decimal

Fudgin [204]

Answer:

0.4375

Step-by-step explanation:

Number of shots attempted by Farah = 84

Number of shots made by Farah = 28

So,

Shots made out of shots attempted will be Equal to

$\frac{28}{64}$

= 0.4375

Thus,

Number of shots made out of number of shots attempted for farah in hockey match equals to 0.4375 .

6 0

4 years ago

What is the determinant of the coefficient matrix of the system<br> –11<br> –2<br> 0<br> 55

Alina [70]

The first two rows of coefficients are identical, so by inspection, the determinant is 0.

7 0

4 years ago

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Refer to the random sample of customer order totals with an average of $78.25 and a population standard deviation of $22.50. a.

zysi [14]

Answer:

a) $78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

b) $78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

c) For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

d) $ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

Step-by-step explanation:

Part a

For this case we have the following data given

$\bar X = 78.25$ represent the sample mean for the customer order totals

$\sigma =22.50$ represent the population deviation

$n= 40$ represent the sample size selected

The confidence level is 90% or 0.90 and the significance level would be $\alpha=0.1$ and $\alpha/2 = 0.05$ and the critical value from the normal standard distirbution would be given by:

$z_{\alpha/2}=1.64$

And the confidence interval is given by:

$\bar X -z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

Part b

The sample size is now n = 75, but the same confidence so the new interval would be:

$78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

Part c

For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

Part d

The margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

3 0

3 years ago