All categories

2 years ago

If the volume of this box was 750 inches what would the value of the hieght have to be

Mathematics

1 answer:

Allushta [10]2 years ago

8 0

The original height of the box is approximately 9.086...

You might be interested in

Carmela mixes 3/4 kilogram of walnuts, 1/2 kilogram of almonds, and 1/4 kilogram of pecans together. She divides the mixed nuts

Evgesh-ka [11]

Amount of walnuts= $\frac{3}{4} kg$

Amount of almonds= $\frac{1}{2} kg$

Amount of pecans= $\frac{1}{4} kg$

Total amount= $\frac{3}{4}+\frac{1}{2}+\frac{1}{4}$

LCM is 4 so sum is = $\frac{3+2+1}{4}=\frac{6}{4}$ = $\frac{3}{2}$

As given, Carmela divides the mixed nuts into 3/10 kilogram bags so number of bags will be:

$\frac{\frac{3}{2}}{\frac{3}{10}}$

= $\frac{3}{2}\times\frac{10}{3}$ = 5

Hence, answer is 5 bags.

5 0

3 years ago

What is the angle, in degrees, when the coordinate is <img src="https://tex.z-dn.net/?f=%28-%5Csqrt%7B2%7D%20%2F2%29%2C%20%5Csqr

Juliette [100K]

Answer:

135°

Step-by-step explanation:

seg AB=seg OB

tan ∠AOB = 1

∠AOB = 45°

∠AOC = 135°

8 0

2 years ago

Write out the form of the partial fraction decomposition of the function. Do not determine the numerical values of the coefficie

Dvinal [7]

For part (a), you have

$\dfrac x{x^2+x-6}=\dfrac x{(x+3)(x-2)}=\dfrac a{x+3}+\dfrac b{x-2}$
$x=a(x-2)+b(x+3)$

If $x=2$ , then $2=b(2-3)\implies b=-2$ .

If $x=-3$ , then $-3=a(-3-2)\implies a=\dfrac35$ .

So,

$\dfrac x{x^2+x-6}=\dfrac 3{5(x+3)}-\dfrac 2{x-2}$

For part (b), since the degrees of the numerator and denominator are the same, you first need to find the quotient and remainder upon division.

$\dfrac{x^2}{x^2+x+2}=\dfrac{x^2+x+2-x-2}{x^2+x+2}=1-\dfrac{x+2}{x^2+x+2}$

In the remainder term, the denominator $x^2+x+2$ can't be factorized into linear components with real coefficients, since the discriminant is negative $(1-4\times1\times2=-7)$ . However, you can still factorized over the complex numbers, so a partial fraction decomposition in terms of complexes does exist.

$x^2+x+2=0\implies x=-\dfrac12\pm\dfrac{\sqrt7}2i$
$\implies x^2+x+2=\left(x-\left(-\dfrac12+\dfrac{\sqrt7}2i\right)\right)\left(x-\left(-\dfrac12-\dfrac{\sqrt7}2i\right)\right)$
$\implies x^2+x+2=\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)$

Then you have

$\dfrac{x+2}{x^2+x+2}=\dfrac a{x+\dfrac12-\dfrac{\sqrt7}2i}+\dfrac b{x+\dfrac12+\dfrac{\sqrt7}2i}$
$x+2=a\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)+b\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)$

When $x=-\dfrac12-\dfrac{\sqrt7}2i$ , you have

$-\dfrac12-\dfrac{\sqrt7}2i+2=b\left(-\dfrac12-\dfrac{\sqrt7}2i+\dfrac12-\dfrac{\sqrt7}2i\right)$
$\dfrac32-\dfrac{\sqrt7}2i=-\sqrt7ib$
$b=\dfrac12+\dfrac3{2\sqrt7}i=\dfrac1{14}(7+3\sqrt7i)$

When $x=-\dfrac12+\dfrac{\sqrt7}2i$ , you have

$-\dfrac12+\dfrac{\sqrt7}2i+2=a\left(-\dfrac12+\dfrac{\sqrt7}2i+\dfrac12+\dfrac{\sqrt7}2i\right)$
$\dfrac32+\dfrac{\sqrt7}2i=\sqrt7ia$
$a=\dfrac12-\dfrac3{2\sqrt7}i=\dfrac1{14}(7-3\sqrt7i)$

So, you could write

$\dfrac{x^2}{x^2+x+2}=1-\dfrac{x+2}{x^2+x+2}=1-\dfrac {7-3\sqrt7i}{14\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)}-\dfrac {7+3\sqrt7i}{14\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)}$

but that may or may not be considered acceptable by that webpage.

5 0

3 years ago

Read 2 more answers

The lines x=0, y=2x-5, and y=mx+9 form a right triangle. find the two possible values of m

Alex17521 [72]

Answer: -1/2, 0

Step-by-step explanation:

x=0 , y=2x-5 and y=mx+9 form a right angle. So, y=mx+9 is either perpendicular to x=0 or y=2x-5 because the angle between x=0 and y=2x-5 is not 90 degrees. The product of slopes of perpendicular lines equals to -1.

Thus, m=-1/2 if it is perpendicular to y=2x-5. And y=c, for some constant if it is perpendicular to x=0. So y=0x+9 fits the bill. (m=0, in this case)

5 0

3 years ago

What is the greatest common factor of 20 and 36? 2 4 5 6

Sindrei [870]

Answer:

GFC = 4

Step-by-step explanation:

Factors of 20 1 2 4 5 10 20

Factors of 36 1 2 3 4 6 9 12 18 36

3 0

2 years ago

Read 2 more answers