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yulyashka [42]
2 years ago
8

What is the angle, in degrees, when the coordinate is

t%7B2%7D%20%2F2%29" id="TexFormula1" title="(-\sqrt{2} /2), \sqrt{2} /2)" alt="(-\sqrt{2} /2), \sqrt{2} /2)" align="absmiddle" class="latex-formula"> ? Pls help thanks
Mathematics
1 answer:
Juliette [100K]2 years ago
8 0

Answer:

135°

Step-by-step explanation:

seg AB=seg OB

tan ∠AOB = 1

∠AOB = 45°

∠AOC = 135°

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C-c+a+ |a|; use a = 4, and c=5
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c-c+a+|a|

5-5+4+|4|

8

Step-by-step explanation:

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Find 30% of 70 whats your right one
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21

Step-by-step explanation:

I hope this helps!

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What is the mode of this data on the quiz scores? 100, 98, 95, 92, 88, 85, 80, 75
larisa86 [58]

Answer:

There is no mode.

Step-by-step explanation:

Be sure to put in there is no mode, don't put in zero. If you put in zero, it will seem like ) is the mode, you know what I mean.

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7 0
3 years ago
The speeds of vehicles traveling on a highway are normally distributed with an unkown population mean and standard deviation. A
Maksim231197 [3]

Answer:

The 90% confidence interval would be given by (60.09;69.91)    

We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =65 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=9 represent the sample standard deviation

n=11 represent the sample size  

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=11-1=10

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,10)".And we see that t_{\alpha/2}=1.81

Now we have everything in order to replace into formula (1):

65-1.81\frac{9}{\sqrt{11}}=60.09    

65+1.81\frac{9}{\sqrt{11}}=69.91

So on this case the 90% confidence interval would be given by (60.09;69.91)    

We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.

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2 years ago
Find ex and Y to the quadrilateral is a parallelogram.
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The diagram is y because it is y to that is because ahhh
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