Answer:
x ≈ 78.7° (in degree)
x ≈ 1.4 (in radians)
Step-by-step explanation:
Given in the question an equation
tan(x) = 5
x = 
x = 78.69
x ≈ 78.7°
In radian:
x ≈ 1.4
1) 12p+12q 2) 11p-11q 3)2p-10q
17.549 is 17.54 rounded to the nearest hundredth
Answer:
The Probability = 0.20
Step-by-step explanation:
From the question stated, the first step to take is to find probability that an employee selected at random will need either eyeglasses or major dental work
Solution
Given
Now,
The exams showed tha the number of employees needed eyeglasses = 8%
Employees that needed major dental work = 15%
Employees that needed both eyeglasses and major dental work =3%
Thus,
The P(needed eyeglasses ) = 8% = 0.08
P(major dental work) = 15% = 0.15
P(eye glasses and major dental work) = 3% = 0.03
The probability that an employee selected at random will need either eyeglasses or major dental work is given as
= P(eye glasses ) + P(major dental work) - P(eyeglasses and major dental work)
= 0.08 + 0.15 - 0.03 = 0.20
Therefore the Probability = 0.20
Answer: see explanation
Step-by-step explanation:
so you have a plane at constant altitudeof 6km (6000m) flying at 800 km/h (222.222 m/s) (see the image)
the plane is moving with constant speed therefore x(t) = 222.222*t => no forces are interacting horizontally with the plane therefore acceleration is 0, then v is constant and x(t) is a linear function which coefficient is v.
now we have a triangle with an angle theta, one side is x(t), and the other is 6000m. we can get theta by tan(theta) = 6000/(222.222*t). 24 minutes are 1440 seconds so if we replace such value, we get the theta angle by solving for theta => theta = arctan(6000/(222.222*1440)) = 0.019 radians or 1.074 degrees. Now if you want to know the exchange rate of theta we have to differentiate the expression with respect to t:

then replace t with 1440 and you will get that theta is changing by -0.000013 (1.3E-5) radians or -7.458E-4 degrees every second which has a lot of sense since the plane is getting out of your line of sight due to the earth's curvature