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deff fn [24]
3 years ago
11

Emily tossed a die onto a black and red checkerboard. what is the probability that it will land with a value of 2, on a red squa

re?
(hint: half the squares on a checkerboard are black)
Mathematics
2 answers:
Oxana [17]3 years ago
7 0
1/2 becuase they are in between i think hope this helps
gregori [183]3 years ago
3 0

It is given that half the squares on a checkerboard are black. Therefore, the other half will be red. Thus, the probability of finding a red square on the checkerboard is: P(red)=\frac{1}{2}

Now, the Probability of a die landing with a value of 2 is:

P(2)=\frac{1}{6}

Therefore, the probability of the event that the die face is a 2 <u>and</u> lands on the red square is:

P(red)\times P(2)=\frac{1}{2}\times \frac{1}{6} =\frac{1}{12}

This can be expressed as percentage as: \frac{1}{12}\times 100\approx 8.33%



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Answer:

A)14v + 16b = 1152

10v + 13b = 925

B)Number of students in a van = 8

Number of students in each bus = 65

C) Elimination method was easier.

Step-by-step explanation:

Let v be the number of students in a van

Let b be number of students in a bus

A) We are told the first school can fill 14 vans and 16 buses with 1152 students

Thus;

14v + 16b = 1152 - - - - - (eq 1)

Also,we are told that the second school can fill 10 vans and 13 buses with 925 students.

Thus;

10v + 13b = 925 - - - - (eq 2)

B) To solve this we will use elimination method.

Multiply eq (1) by 5 and multiply eq (2) by 7 to give;

70v + 80b = 5760 - - - - eq(3)

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Subtract eq(3) from eq(4) to give;

91b - 80b = 6475 - 5760

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Put 65 for b in eq(3) to give;

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70v = 5760 - 80(65)

70v = 560

v = 560/70

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Number of students in each bus = 65

C) Elimination method was used because in both equations, we had different digits attached and so it would have been more tedious to use substitution method or graphical method. Thus, elimination method was more easier.

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