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3 years ago

No link need right answer

Mathematics

1 answer:

Novay_Z [31]3 years ago

3 0

= 0.125 cubic inches :))))))

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11) Write the equation of the circle with center (7, 3) and a radius of 2.

Minchanka [31]

(x - 7)² + (y - 3)² = 4 is your equation.

5 0

3 years ago

Can someone pleaseeee help and if you’re correct i’ll give brainliest

Tasya [4]

Answer:area of the circle=πr²

3.14 =3.14 ×r²

r²= 1

r. =1 millimeters

6 0

3 years ago

What effect does multiplying a number by 1/10 have on the number?

antoniya [11.8K]

$x \times \frac{1}{10} = \frac{x}{10}$

Divides it by 10.

8 0

3 years ago

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Carmen has a rope 54 feet long. She wants to cut it into 6-foot lengths to make jump ropes for the members of the jump roping te

Ilia_Sergeevich [38]

54 divided by 6 is 9. she can 9 times

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4 years ago

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For what values of θ is sinθ < cosθ when 0 ≤ θ < π ?

zysi [14]

<h3>Answer: $0 \le \theta < \frac{\pi}{4}$ </h3>

=========================================================

How to get this answer:

Use the unit circle to note that $\sin\theta = \cos\theta = \frac{\sqrt{2}}{2}$ when $\theta = \frac{\pi}{4}$ (aka 45 degrees)

Beyond this point, cosine is smaller than sine. This means that anything from 0 to pi/4 will have sine be smaller than cosine. It might help to graph y = sin(x) and y = cos(x) on the interval from x = 0 to x = pi.

The two curves y = sin(x) and y = cos(x) intersect at the point $\left(\frac{\pi}{4}, \frac{\sqrt{2}}{2}\right)$

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Here's a more detailed picture of whats going on.

$\sin \theta < \cos \theta\\\\\sin \theta < \sqrt{1-\sin^2\theta}\\\\\sin^2 \theta < 1-\sin^2\theta \\\\2\sin^2 \theta < 1\\\\\sin^2 \theta < \frac{1}{2}\\\\\sin \theta < \sqrt{\frac{1}{2}}\\\\\sin \theta < \frac{1}{\sqrt{2}}\\\\\sin \theta < \frac{\sqrt{2}}{2}\\\\\theta < \arcsin\left(\frac{\sqrt{2}}{2}\right)\\\\\theta < \frac{\pi}{4}\\\\$

Intersect the intervals $0 \le \theta < \pi$ and $\theta < \frac{\pi}{4}$ and you'll end up with the final answer $0 \le \theta < \frac{\pi}{4}$

4 0

3 years ago