<h3>Given</h3>
- room height is x feet
- room length is 3x feet
- room width is 3x feet
- a door 3 ft wide by 7 ft tall
<h3>Find</h3>
- The net area of the wall, excluding the door
<h3>Solution</h3>
The area of the wall, including the door, is the room perimeter multiplied by the height of the room. The room perimeter is the sum of the lengths of the four walls.
... gross wall area = (3x +3x +3x +3x)·x = 12x²
The area of the door is the product of its height and width.
... door area = (7 t)×(3 ft) = 21 ft²
Then the net wall area, exclusive of the door is ...
... net wall area = gross wall area - door area
... net wall area = 12x² -21 . . . . square feet
Answer:
LOL i don't even know
Step-by-step explanation:
Answer:
12.5
Step-by-step explanation:
In order to solve, we need to add 9 to both sides of the equation:
<u>Our sum applied:</u>
b=12.5
Answer:
Step-by-step explanation:
To do this, we must use the unit circle. At the angle 
the coordinate pair is (
, 
) and the hypotenuse is 1
Now that we know these we can start using the trig functions
sin = y
cos = x
tan = 
And the other functions would be the reciprocal of these
csc = 
sec = 
cot = 
This would mean that
sinx =
cosx =
tanx =
or 
if you're supposed to rationalize your denominators
cscx = 2
secx = 
or 
cot = 
<span>percent of 64 is 8 means number/100 * 64 = 8.n/100 * 64 = 8n/100 = 8/64n = 8*100/64 = 25/2 = 12.58 is 12.5% of 64</span>
