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3 years ago

10

Larry was paid a total of $30 for raking leaves for 8 hours of work. This rate is constant. What will be the total amount that L

arry will be paid for raking leaves for 20 hours of work

1 answer:

adelina 88 [10]3 years ago

7 0

Answer:

Hi! The correct answer is $75 for 20 hours.

Step-by-step explanation:

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William can eat 17 hot dogs in 5 minutes. If he continues to eat at the same rate, how long will it take him to eat 68 hotdogs.

lidiya [134]

Answer:

20 Minutes

Step-by-step explanation:

First find out how many he eats per minute. 17/5 = 3.4

Then multiply 3.4 by all the answers until you get the right answer.

5 0

3 years ago

A store plans to sell two different game consoles, the YuuMi and the ZBox. The store’s wholesale cost for a YuuMi is $250, and t

strojnjashka [21]

9514 1404 393

Answer:

Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
Objective formula: p = 45x +50y
200 YuuMi and 50 ZBox should be stocked
maximum profit is $11,500

Step-by-step explanation:

Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...

250x +400y ≤ 70000

The number sold will be at most 250 units, so that constraint is ...

x + y ≤ 250

Additionally, we require x ≥ 0 and y ≥ 0.

__

A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...

profit = 45x +50y

__

A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).

200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.

4 0

3 years ago

Pleaseee help, Solve for x and y :3

irina1246 [14]

Answer:

x = $\sqrt{6}$ , y = 2 $\sqrt{3}$

Step-by-step explanation:

using the tangent ratio and the exact value tan45° = 1 , then

tan45° = $\frac{opposite}{adjacent}$ = $\frac{x}{\sqrt{6} }$ = 1 , then

x = $\sqrt{6}$

----------------------------------

using the cosine ratio in the right triangle and the exact value

cos45° = $\frac{1}{\sqrt{2} }$ , then

cos45° = $\frac{adjacent}{hypotenuse}$ = $\frac{\sqrt{6} }{y}$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

y = $\sqrt{6}$ × $\sqrt{2}$ = $\sqrt{12}$ = 2 $\sqrt{3}$

6 0

2 years ago

Lol help anyone?PLEASE !!

Savatey [412]

Answer:

B: 1/5 = 4/x

Step-by-step explanation:

1cm = 5km

4cm = 20km

5 0

3 years ago

Read 2 more answers

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $\displaystyle y = \frac{3}{2x^2}$ <u />

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

<u>Step 2: Differentiate</u>

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

<u>Step 3: Solve</u>

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

3 years ago