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2 years ago

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Hii, Ok so basically I really need help with these questions they are really difficult and don't worry rewards are plenty a come

. On the last question whoever give the right answer and is the quickest will get brainliest. But do not worry whoever answers this question will get a
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So you may be wondering what the question is well take a look oh and by the way please do not give a random answer and its a maths question

Given that angle A = 284 degrees, work out x

1 answer:

posledela2 years ago

5 0

So begin by doing 360-284=76
90+76=166
180-166=14

X=14

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Laura wants to rent a boat and spend less than $69. The boat costs $8 per hour, and Laura has a diacount coupon for $3 off. What

julia-pushkina [17]

Answer:

69+3devide 8 = 9 hours laura spend on bout

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3 years ago

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Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i

sp2606 [1]

i. The Lagrangian is

$L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)$

with critical points whenever

$L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4$

$L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_\lambda=4x^2+y^2-9=0$

If $x=0$ , then $L_\lambda=0\implies y=\pm3$ .
If $y=0$ , then $L_\lambda=0\implies x=\pm\dfrac32$ .
Either value of $\lambda$ found above requires that either $x=0$ or $y=0$ , so we get the same critical points as in the previous two cases.

We have $f(0,-3)=9$ , $f(0,3)=9$ , $f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25$ , and $f\left(\dfrac32,0\right)=\dfrac{729}4$ , so $f$ has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

$L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)$

with critical points whenever

$L_x=2\lambda x=0\implies x=0$ (because we assume $\lambda\neq0$ )

$L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda$

$L_\lambda=x^2+y^2+z^2-36=0$

If $x=y=0$ , then $L_\lambda=0\implies z=\pm6$ .
If $\lambda=-1$ , then $z=-5$ , and with $x=0$ we have $L_\lambda=0\implies y=\pm\sqrt{11}$ .

We have $f(0,0,-6)=60$ , $f(0,0,6)=-60$ , $f(0,-\sqrt{11},-5)=61$ , and $f(0,\sqrt{11},-5)=61$ . So $f$ has a maximum value of 61 and a minimum value of -60.

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3 years ago

A local nonprofit organization is selling popcorn to raise money for hurricane relief. The organization paid $4 per bag for the

Bezzdna [24]

Percent markup is 125% sorry if I’m wrong

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2 years ago

The demand function for a product is modeled by p = 400 − 4x, 0 ≤ x ≤ 100, where p is the price per unit (in dollars) and x is t

lawyer [7]

Answer:

Demand is Elastic when Price > 200 ; Demand is inelastic when Price < 200

Step-by-step explanation:

p = 400 - 4x

4x = 400 - p

x = (400 - p) / 4 → x = 100 - p/4

Elasticity of demand [ P ed ] = (Δx / Δp) x (p / x)

Δx / Δp [Differentiating x w.r.t p] = 0 - 1/4 → = -1/4

P ed = <u>-1</u> x<u> p </u>

4 (400 - p)/4

= <u>-1</u> x <u> 4p </u> = -p / (400-p)

4 (400 - p)

Price Elasticity of demand : only magnitude is considered, negative sign is ignored (due to negative price demand relationship as per law of demand).

So, Ped = p / (400 - p)

Demand is Elastic when P.ed > 1

p / (400-p) > 1

p > 400 - p

p + p > 400 → 2p > 400

p > 400 / 2 → p > 200

Demand is inelastic when P.ed < 1

p / (400-p) < 1

p < 400 - p

p + p < 400 → 2p < 400

p < 400 / 2 → p < 200

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3 years ago

the product of two consecutive integers is 420. an equation is written in standard form to solve for the smaller integer by fact

Xelga [282]

Start by writing your own expression.

x is the smaller number and x + 1 is the next number

x(x + 1) = 420

x^2 + x - 420 =0 ⇒ constant = -420

6 0

2 years ago

Read 2 more answers