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bonufazy [111]
2 years ago
7

Hii, Ok so basically I really need help with these questions they are really difficult and don't worry rewards are plenty a come

. On the last question whoever give the right answer and is the quickest will get brainliest. But do not worry whoever answers this question will get a
1. Thank you *heart*
2. 5 star rating
3. Comment

So you may be wondering what the question is well take a look oh and by the way please do not give a random answer and its a maths question

Given that angle A = 284 degrees, work out x

Mathematics
1 answer:
posledela2 years ago
5 0
So begin by doing 360-284=76
90+76=166
180-166=14

X=14
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Laura wants to rent a boat and spend less than $69. The boat costs $8 per hour, and Laura has a diacount coupon for $3 off. What
julia-pushkina [17]

Answer:

69+3devide 8 = 9 hours laura spend on bout

6 0
3 years ago
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Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i
sp2606 [1]

i. The Lagrangian is

L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)

with critical points whenever

L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4

L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1

L_\lambda=4x^2+y^2-9=0

  • If x=0, then L_\lambda=0\implies y=\pm3.
  • If y=0, then L_\lambda=0\implies x=\pm\dfrac32.
  • Either value of \lambda found above requires that either x=0 or y=0, so we get the same critical points as in the previous two cases.

We have f(0,-3)=9, f(0,3)=9, f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25, and f\left(\dfrac32,0\right)=\dfrac{729}4, so f has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)

with critical points whenever

L_x=2\lambda x=0\implies x=0 (because we assume \lambda\neq0)

L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1

L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda

L_\lambda=x^2+y^2+z^2-36=0

  • If x=y=0, then L_\lambda=0\implies z=\pm6.
  • If \lambda=-1, then z=-5, and with x=0 we have L_\lambda=0\implies y=\pm\sqrt{11}.

We have f(0,0,-6)=60, f(0,0,6)=-60, f(0,-\sqrt{11},-5)=61, and f(0,\sqrt{11},-5)=61. So f has a maximum value of 61 and a minimum value of -60.

5 0
3 years ago
A local nonprofit organization is selling popcorn to raise money for hurricane relief. The organization paid $4 per bag for the
Bezzdna [24]
Percent markup is 125% sorry if I’m wrong
5 0
2 years ago
The demand function for a product is modeled by p = 400 − 4x, 0 ≤ x ≤ 100, where p is the price per unit (in dollars) and x is t
lawyer [7]

Answer:

Demand is Elastic when Price > 200 ; Demand is inelastic when Price < 200

Step-by-step explanation:

p = 400 - 4x

4x = 400 - p

x = (400 - p) / 4 → x = 100 - p/4

Elasticity of demand  [ P ed ] = (Δx / Δp) x (p / x)

Δx / Δp  [Differentiating x w.r.t p]  = 0 - 1/4  → = -1/4

P ed =  <u>-1</u> x<u> p </u>

            4   (400 - p)/4

= <u>-1</u> x <u> 4p </u>              = -p / (400-p)

  4   (400 - p)

Price Elasticity of demand : only magnitude is considered, negative sign is ignored (due to negative price demand relationship as per law of demand).

So, Ped = p / (400 - p)

Demand is Elastic when P.ed > 1

p / (400-p)  > 1

p > 400 - p

p + p > 400  → 2p > 400

p > 400 / 2 →  p > 200

Demand is inelastic when P.ed < 1

p / (400-p)  < 1

p < 400 - p

p + p < 400  → 2p < 400

p < 400 / 2 →  p < 200

4 0
3 years ago
the product of two consecutive integers is 420. an equation is written in standard form to solve for the smaller integer by fact
Xelga [282]
Start by writing your own expression.

x is the smaller number and x + 1 is the next number

x(x + 1) = 420

x^2 + x - 420 =0 ⇒ constant = -420
6 0
2 years ago
Read 2 more answers
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