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3 years ago

How to write y-1=-x-6 In slope intercept form

Mathematics

2 answers:

DiKsa [7]3 years ago

4 0

y=-x-5. you just need to add 1 to another side to get rid of 1 from the left side

Ne4ueva [31]3 years ago

3 0

Answer:

y = -x -5

Step-by-step explanation:

Note that the slope-intercept form is: y = mx + b

Isolate the b. Note the equal sign, what you do to one side, you do to the other. Add 1 to both sides

y - 1 (+1) = -x - 6 (+1)

y = -x - 6 + 1

y = -x - 5

~Elite

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Read 2 more answers

Vic is standing on the ground at a point directly south of the base of the CN Tower and can see the top when looking at an angle

Sindrei [870]

The angle of elevation of 61° and 72° with the height of the tower being 553.3 m. gives Vic's distance from Dan as approximately 356 meters.

<h3>How can the distance between Vic and Dan be calculated?</h3>

Location of Vic relative to the tower = South

Vic's sight angle of elevation to the top of the tower = 61°

Dan's location with respect to the tower = West

Dan's angle of elevation in order to see the top of the tower = 72°

Height of the tower = 553.3m

$tan( \theta) = \frac{opposite}{adjacent}$

$tan( 61 ^{ \circ}) = \frac{553.3}{ Vic' s\: distance \: to \: tower}$

$distance = \frac{553.3}{tan ( {61}^{ \circ} )} = 306.7$

Vic's distance from the tower ≈ 306.7 m

Similarly, we have;

$Dan's distance = \frac{553.3}{tan ( {72}^{ \circ} )} = 179.8$

Dan's distance from the tower ≈ 179.8 m

Given that Vic and Dan are at right angles relative to the tower (Vic is on the south of the tower while Dan is at the west), by Pythagorean theorem, the distance between Vic and Dan <em>d </em>is found as follows;