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3 years ago

11

During scuba lessons, Sue dove 30 feet, Harriet dove 120 feet, and Kathy dove 90 feet.What integers represent these depths? Orde

r the integers from least to greatest. (Remember, the depth is underneath the surface of the water.)

1 answer:

aleksley [76]3 years ago

3 0

120, 90, 30 if you're going from the depths of the water to water level

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. If mZJ= (7x + 13)", mZK = (83 - 2x), and

OLga [1]

Answer:

m∠J = 76°
m∠K = 65°

Step-by-step explanation:

The sum of angle measures is ...

(7x +13)° +(83 -2x)° = 141°

5x +96 = 141 . . . . . collect terms, divide by °

5x = 45 . . . . . . . . . subtract 96

x = 9 . . . . . . . . . . . divide by 5

7x +13 = 7·9 +13 = 76 . . . . . find m∠J

m∠J = 76°

m∠K = 141° -76°

m∠K = 65°

8 0

3 years ago

Find the area of an octagon with a radius of 6 meters

never [62]

A regular octagon has all its eight sides congruent. The line segments joining each of the vertices of a regular octagon to its center are called the radii of the octagon. These 8 radii divide a regular octagon into 8 congruent isosceles triangles. Area of each isosceles triangle is

$A_{triangle}=\dfrac{1}{2}a^2\sin \alpha$ ,

where a is length of the side of the octagon and $\alpha$ is the angle between two radii of the octagon.

In regular octagon

$\alpha=\dfrac{360^{\circ}}{8}=45^{\circ}$ .

Then the area of regular octagon is

$A_{octagon}=8A_{triangle}=8\cdot \dfrac{1}{2}a^2\sin \alpha=4\cdot (6)^2\cdot \sin 45^{\circ}=4\cdot 36\cdot \dfrac{\sqrt{2}}{2}=72\sqrt{2}$ sq. m.

Answer: $A_{octagon}=72\sqrt{2}$ sq. m.

7 0

4 years ago

Ryan, Jessica, and Mark each solved this system of equations. All of their answers are different. Find and explain the mistakes.

Stella [2.4K]

It's not possible to do any of that without seeing any of their work.

By the way, that system of equations has no solution.

6 0

3 years ago

Read 2 more answers

Solve for x in a right triangle (show work)

AnnZ [28]

Answer:

35.09°

Step-by-step explanation:

You can use cos theta to find the value of x.

Let us solve now.

They have already given the lengths of the hypotenuse and adjacent.

Hypotenuse = 33

Adjacent = 27

Let us solve now.

Cos x = Adjacent ÷ Hypotenuse

Cos x = 27 ÷ 33

Cos x = 0.8181

x = Cos⁻¹ 0.8181

x = 35.09°

Hope this helps you :-)

Let me know if you have any other questions :)

5 0

2 years ago

What is the value of the exponential function f (x)=2 times (1/3)^x when x= -2

frutty [35]

Answer:

18

Step-by-step explanation:

f(x) = 2(1/3)^x

[x = -2]

f(-2) = 2(1/3)⁻²

= 2(9)

= 18

5 0

2 years ago