Answer:
Part 1)
![m=170\°](https://tex.z-dn.net/?f=m%3D170%5C%C2%B0)
Part 2)
![x=-5, x=1](https://tex.z-dn.net/?f=x%3D-5%2C%20x%3D1)
![m=-10, m=14](https://tex.z-dn.net/?f=m%3D-10%2C%20m%3D14)
Step-by-step explanation:
we know that
In a parallelogram opposite sides and opposite angles are congruent, and consecutive angles are supplementary
Part 1)
<u>Find the value of x</u>
----> opposite sides are congruent
solve for x
<u>Find the value of m</u>
----> consecutive angles are supplementary
solve for m
![m=180\°-10\°=170\°](https://tex.z-dn.net/?f=m%3D180%5C%C2%B0-10%5C%C2%B0%3D170%5C%C2%B0)
Part 2)
<u>Find the value of x</u>
---> opposite sides are congruent
using a graphing tool
see the attached figure N 1
The solutions are
![x=-5, x=1](https://tex.z-dn.net/?f=x%3D-5%2C%20x%3D1)
<u>Find the value of m</u>
---> opposite sides are congruent
solve for m
using a graphing tool
see the attached figure N 2
The solutions are
![m=-10, m=14](https://tex.z-dn.net/?f=m%3D-10%2C%20m%3D14)
the line will rise more sharply than before, the slope is steeper, increased from the 2 to 2.5.
Answer:
Slope is Zero 0
Step-by-step explanation:
this is because the line is horizontal and therefore has no slope
Let x + 1.5 be length of segment above left hand
Let 2x be length of segment below left hand
15 = x + 1.5 + 2x
15 = 3x + 1.5
15 - 1.5 = 3x
13.5 = 3x
13.5/3= 3x/3
4.5 = x
x = 4.5
This is the length above the left hand.
2x must be then 4.5*2 = 9 foot
This is the length below the left hand.
Checking
4.5 + 9 + 1.5 = 15 foot
Adding length below left hand & length of left hand to right hand:
9 + 1.5 = 10.5
The right hand is hence 10.5 foot far up the pole.
Answer:
![\frac{x}{y}=1.3](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D1.3)
Step-by-step explanation:
<u>Informação recuperada:</u>
(UFRGS) Se 10x = 20y , atribuindo 0,3 para log 2 , então o valor de x/y é
1) Primeiro, passando o 10 para o 2º membro como base do logaritmo:
![10x=20y \Rightarrow x=log_{10}20y](https://tex.z-dn.net/?f=10x%3D20y%20%5CRightarrow%20x%3Dlog_%7B10%7D20y)
2) Aplicando a propriedade do produto de logaritmo:
![log(AB)= logA+logB](https://tex.z-dn.net/?f=log%28AB%29%3D%20logA%2BlogB)
![x=log_{10}20y \Rightarrow x=log(2+10)y\Rightarrow x=(0.3+1)y \Rightarrow x=1.3y](https://tex.z-dn.net/?f=x%3Dlog_%7B10%7D20y%20%5CRightarrow%20x%3Dlog%282%2B10%29y%5CRightarrow%20x%3D%280.3%2B1%29y%20%5CRightarrow%20x%3D1.3y)
3) Como quero o quociente divido ambos os lados por y
![\frac{x}{y}=\frac{1.3y}{y}\Rightarrow \frac{x}{y}=1.3](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D%5Cfrac%7B1.3y%7D%7By%7D%5CRightarrow%20%5Cfrac%7Bx%7D%7By%7D%3D1.3)