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tamaranim1 [39]
3 years ago
5

I can't find the surface area, is this confusing me.

Mathematics
2 answers:
Fed [463]3 years ago
3 0
<span>Find the area of two sides (Length*Height)*2 sidesFind the area of adjacent sides (Width*Height)*2 sidesFind the area of ends (Length*Width)*2 ends<span>Add the three areas together to find the surface area</span></span>
4vir4ik [10]3 years ago
3 0
Length times height to find a square or rectangle and / or square

To find triangle its length times night divided by 2

6•20
+
8•20
+
20•10
+
In this case you can multiply 8 times 6 only once Because there is another triangle exactly the same

120 + 160 + 200 + 48

Answer- 528
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Hello, Can I get some help with #30 a and b, please? Don't forget to show your work.
Murljashka [212]

Answer:

a. dy/dx = -2/3

b. dy/dx = -28

Step-by-step explanation:

One way to do this is to assume that x and y are functions of something else, say "t", then differentiate with respect to that. If we write dx/dt = x' and dy/dt = y', then the required derivative is y'/x' = dy/dx.

a. x'·y^3 +x·(3y^2·y') = 0

y'/x' = -y^3/(3xy^2) = -y/(3x)

For the given point, this is ...

dy/dx = -2/3

___

b. 2x·x' +x^2·y' -2x'·y^3 -2x·(3y^2·y') + 0 = 2x' + 2y'

y'(x^2 -6xy^2 -2) = x'(2 -2x +2y^3)

y'/x' = 2(1 -x +y^3)/(x^2 +6xy^2 -2)

For the given point, this is ...

dy/dx = 2(1 -0 +27)/(0 +0 -2)

dy/dx = -28

_____

The attached graphs show these to be plausible values for the derivatives at the given points.

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Step-by-step explanation:

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