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3 years ago

I can't find the surface area, is this confusing me.

Mathematics

2 answers:

Fed [463]3 years ago

3 0

Find the area of two sides (Length*Height)*2 sidesFind the area of adjacent sides (Width*Height)*2 sidesFind the area of ends (Length*Width)*2 endsAdd the three areas together to find the surface area

4vir4ik [10]3 years ago

3 0

Length times height to find a square or rectangle and / or square

To find triangle its length times night divided by 2

6•20
+
8•20
+
20•10
+
In this case you can multiply 8 times 6 only once Because there is another triangle exactly the same

120 + 160 + 200 + 48

Answer- 528

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2 (t-4) + 1 math I ready

Roman55 [17]

Answer:

2t-7

Step-by-step explanation:

Not sure what you need ;( hope this helps!

6 0

3 years ago

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Find the length of the curve. R(t) = 7t, 3 cos(t), 3 sin(t) , −2 ≤ t ≤ 2

Leviafan [203]

we are given

$r(t)=(7t,3cos(t),3sin(t))$

we can find x , y and z

$x=7t,y=3cos(t),z=3sin(t))$

now, we can use arc length formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

now, we can find derivative

$x'=7,y'=-3sin(t),z'=3cos(t))$

now, we can plug values

and we get

$L=\int _{-2}^2\sqrt{7^2+\left(-3\sin \left(t\right)\right)^2+\left(3\cos \left(t\right)\right)^2}dt$

$L=\int _{-2}^2\sqrt{7^2+9}dt$

$=\sqrt{58}\cdot \:2-\left(-2\sqrt{58}\right)$

$L=4\sqrt{58}$ ...........Answer

8 0

3 years ago

I need help with this answer?

Ipatiy [6.2K]

Answer:

The value of angle A is approximately 41.8.

Step-by-step explanation:

In order to find the value of angle A, I used the inverse sine function, where I input a ratio between the opposite and hypotenuse: 4/6, and got the answer.

3 0

2 years ago

3(8 - 2x) + 2(7x -19) simplify

Rina8888 [55]

The answer is -14+8x

4 0

3 years ago

Which of the following is equivalent to (16^3/2)^1/2? 6 8 12 64

Pani-rosa [81]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
\left( 16^{\frac{3}{2}} \right)^{\frac{1}{2}}\implies 16^{\frac{3}{2}\cdot \frac{1}{2}}\implies 16^{\frac{3}{4}}\qquad \boxed{16=2^4}\qquad (2^4)^{\frac{3}{4}}\implies 2^{4\cdot \frac{3}{4}}
\\\\\\
2^3\implies 8$

6 0

3 years ago

Read 2 more answers