1. The right answer is enzymes
NADPH are molecules which are produced during reduction of metabolites (for example glucose metabolism, lipid metabolism...)
2. The right answer is enzymes.
<span>The dark reactions (carbon cycle) act by the reduction of carbon dioxides (CO2) to the level of a carbohydrate (like fructose).
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3. The right answer is ATP.
ATP, or adenosine triphosphate, is a nucleotide of the purine family used to store and transport energy (purines are nitrogenous bases).
4. The right answer is the Calvin cycle.
The Calvin cycle is a series of biochemical reactions that take place in plant chloroplasts. The Calvin cycle makes it possible to manufacture glucose, an energy molecule, from carbon dioxide. This is called carbon fixation.
5. The right answer is NADH
The overall assessment of glycolysis is:Glucose + 2 ADP + 2 Pi + 2 NAD + -----> 2 pyruvate + 2 ATP + 2 H2O + 2 NADH
As we can see, the glycolysis produce indeed 2NADH from a reduction of metabolites during the process.
6. The right answer is Glycolysis.
Glycolysis is the first chain of carbohydrate catabolism, it is carried out in the cytosol by soluble enzymes and anaerobically (without oxygen supply). Its function is the synthesis of a molecule rich in energy, as well as the formation of pyruvate which will have several destinies, including the Krebs cycle.
<span>The Krebs cycle (or tricarboxylic cycle or citric acid cycle) is the energy platform of the cell, continuing the catabolism of carbohydrates after glycolysis. It is realized in the mitochondrial matrix and is done exclusively in aerobic.</span>
No they don't
For example humans. Technically humans are place below a wild predators such as sharks in trophic levels.
But the fact is we can eat sharks. So , organisms don't always stay in the same level
The answer would be D because it leaves you thinking about what will happen next. Hope this helped you out .
Answer:
transcription of mRNA from DNA
small ribosomal subunit binds to mRNA
initiation complex formed with addition of large ribosomal subunit
translocation
codon recognition (non-initiating site)
peptide bond formation
ribosome reads a stop codon
polypeptide chain is released from the P site
ribosomal subunits dissociate
Explanation:
The above describes the process of translation in the ribosome. After transcription of DNA to mRNA, the mRNA is taken to the ribosome to undergo translation, here the mRNA binds to the small ribosomal subuits and to other initiation factors; binding at the mRNA binding site on the small ribosomal subunit then the Large ribosomal subunits joins in.
Translation begins (codon recognition; initiating site) at the initiation codon AUG on the mRNA with the tRNA bringing its amino acid (methionine in eukaryotes and formyl methionine in prokaryotes) forming complementary base pair between its anticodon and mRNA's AUG start codon. Then translocation occurs with the ribosome moving one codon over on the mRNA thus moving the start codon tRNA from the A site to the P site, then codon recognition occurs (non-initiating site again) which includes incoming tRNA with an anticodon that is complementary to the codon exposed in the A site binds to the mRNA.
Then peptide bond formation occurs between the amino acid carried by the tRNA in the p site and the A site. When the ribosome reads a stop codon, the process stops and the polypeptide chain produced is released and the ribosomal subunits dissociates.