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Citrus2011 [14]
3 years ago
10

Y = 6 when x = 30, what is y when x = 6

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0
30 divided by 6 is 5
6 divided by 5 is 1. 2
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15 is what percent of 90?​
Alika [10]
15 is 16.66666 percent of 90.
7 0
3 years ago
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1, 1, 4, 7, 8, 8, 8, 11, 15<br> What is the mode of this list of numbers?<br><br> answer asap!!!!
wlad13 [49]

Answer:

8

Step-by-step explanation:

its eight...........................

7 0
3 years ago
Read 2 more answers
All students = 700
Sedaia [141]

Answer:

  • See below

Step-by-step explanation:

<u>Given:</u>

  • Total number = 700
  • Off grid class = 450
  • Online class = 320
  • Both = 275

<u>Based on the given we find the following</u>

1) <u>Off-grid class only:</u>

  • 450 - 275 = 175

3) <u>Online class only:</u>

  • 320 - 275 = 45

2) <u>None of the classes:</u>

  • 700 - (175 + 275 + 45) = 205

4) <u>Not online:</u>

  • 700 - 320 = 380

5) <u>Not off-grid:</u>

  • 700 - 450 = 250
7 0
3 years ago
A and b are positive integers and a–b = 3. Evaluate the following:
yulyashka [42]

1/27

1/27

125

Step-by-step explanation:

Given that,

a - b = 3

9^(1/2b) /3^a = 3^(2/2b) /3^a

= 3^b/3^a

= 3^(b-a)

= 3^(-3)

= 27^(-1)

= 1/27

27^(1/3b) /9^(1/2a) = 3^(3/3b) /3^(2/2a)

= 3^b/3^a

= 3^(b-a)

= 3^(-3)

= 27^(-1)

= 1/27

125^(1/3a) /25^(1/2b) = 5^(3/3a) /5^(2/2b)

= 5^a/5^b

= 5^(a- b)

= 5^3

= 125

6 0
3 years ago
The lengths of bolts in a batch are distributed normally with a mean of 3 cm and a standard
ValentinkaMS [17]

Answer:

0.8413 = 84.13% probability that a bolt has a length greater than 2.96 cm.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 3 cm and a standard deviation of 0.04 cm.

This means that \mu = 3, \sigma = 0.04

What is the probability that a bolt has a length greater than 2.96 cm?

This is 1 subtracted by the p-value of Z when X = 2.96. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.96 - 3}{0.04}

Z = -1

Z = -1 has a p-value of 0.1587.

1 - 0.1587 = 0.8413

0.8413 = 84.13% probability that a bolt has a length greater than 2.96 cm.

3 0
3 years ago
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