Therefore, f(x) = 2x + 3 is your derivative function, and you need to find the original curve. So find the antiderivative using the given conditions...
∫f(x) = ∫2x + 3 dx
F(x) = x^2 + 3x + C
2 = (1)^2 + 3(1) + C
2 = 4 + C
C= -2
Therefore, the curve is F(x) = x^2 + 3x - 2
Proof: The derivative is the slope at every (x, y) point. The derivative of F(x) comes out to be 2x + 3, so we have found the curve. Plug in x = 1, and y = 2, so the conditions have been met.
<span>Hope I helped.</span>
Convert all of them in decimals
3 ÷ 10 = 0.3
0.4
35% ÷ 100 = 0.35
Order from least to greatest--
3/10, 35%, 0.4
3/10 is the smallest
Answer:
72°
Step-by-step explanation:
tan x= PN/OP=95/31
⇒x ≈ 72°
Step-by-step explanation:
b(n) = b(1) + (n-1) d, where d is the difference,
d = 13-(-5) = 18
b(n) = (-5) + (n-1)(18)
= -5 +18n -18
b(n) = 18n -23