Answer:
its b
Step-by-step explanation:
For question number 3
-7, 7, 6, -4,
4, -2, -1, 1
0, 2, 3, -3,
5, -5, -6, 8
For question number 4:
-4, 1, -10, 3,
-9, 2, -3, 0,
5, -8, -1, -6,
-2, -5, 4, -7
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer to your problem is:
1 411/500
I believe XD.
Answer:
Step-by-step explanation:
it is an adjacent/linear pair