Answer : The dissociation constant of the PFK‑inhibitor complex is, 5 µM
Explanation :
The expression for reversible competitive inhibition when apparent Km affected by addition of the inhibitor is:
![K_m_a=K_m[1+\frac{I}{K_i}]](https://tex.z-dn.net/?f=K_m_a%3DK_m%5B1%2B%5Cfrac%7BI%7D%7BK_i%7D%5D)
where,
= apparent value = 52 µM
= Michaelis–Menten constant = 40 µM
I = inhibitor concentration = 1.5 µM
= dissociation constant of the PFK‑inhibitor complex
Now put all the given values in the above formula, we get:
![52\mu M=40\mu M[1+\frac{1.5\mu M}{K_i}]](https://tex.z-dn.net/?f=52%5Cmu%20M%3D40%5Cmu%20M%5B1%2B%5Cfrac%7B1.5%5Cmu%20M%7D%7BK_i%7D%5D)
Therefore, the dissociation constant of the PFK‑inhibitor complex is, 5 µM
Isotonic since in a hypertonic solution the cell would shrivel up and in a hypotonic solution it would lyse (burst).
All organisms arose from a single common ancestor.
An endosymbiont or endobiont is any organism that lives inside the frame or cells of some other organism most often, though no longer continually, in a mutualistic relationship.
Bacterial endosymbionts result in dramatic phenotypes in their arthropod hosts, including cytoplasmic incompatibility, feminization, parthenogenesis, male killing, parasitoid protection, and pathogen blocking.
Endosymbionts, such as Wolbachia, Rickettsia, and Cardinium, are a type of bacteria generally located in arthropod species inclusive of bugs, spiders, crustaceans, and mites, in addition to other invertebrates along with filarial nematodesEndosymbiosis is a form of symbiosis in which the symbiont lives in the body of its host and the symbiont in an endosymbiosis is known as an endosymbiont.
Learn more about endosymbiotic here;-brainly.com/question/1698852
#SPJ4
The younger rock would be black and have like no stains and it would not be as dirty as the older rock hope this helps!!1
