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Ede4ka [16]
3 years ago
10

Consider two copper wires. One has twice the length and twice the cross-sectional area of the other. How do the resistances of t

hese two wires compare? A) Both wires have the same resistance. B) The shorter wire has twice the resistance of the longer wire. The longer wire has twice the resistance of the shorter wire. D) The longer wire has four times the resistance of the shorter wire. E) The shorter wire has four times the resistance of the longer wire.
Physics
1 answer:
Makovka662 [10]3 years ago
7 0

Answer:

option (a)

Explanation:

Wire 1:

length = 2L

Area = 2 A

Wire 2: length = L

Area = A

As we know that the resistance of a wire is directly proportional to the length of the wire and inversely proportional to the area of crossection of the wire.

Let ρ be the resistivity of the cooper wire.

Resistance of wire 1

R1 = ρ x 2L / 2 A = ρ L / A

Resistance of wire 2:

R2 = ρ x L /  A = ρ L / A

As R1 = R2

It means both the wires have same resistance.

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Determine the specific heat of a certain metal if a 450 gram sample of it loses 34 500 Joules of heat as its temperature starts
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Answer:

c = 0.4356 J/gK

Explanation:

Given the following data;

Mass = 450 grams

Initial temperature, T1 = 150°C

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To find the specific heat capacity of the metal;

Heat capacity is given by the formula;

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Converting the temperature in Celsius to Kelvin, we have;

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Substituting into the equation, we have;

c = \frac {34500}{450*176}

c = \frac {34500}{79200}

c = 0.4356 J/gK

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