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Ede4ka [16]
3 years ago
10

Consider two copper wires. One has twice the length and twice the cross-sectional area of the other. How do the resistances of t

hese two wires compare? A) Both wires have the same resistance. B) The shorter wire has twice the resistance of the longer wire. The longer wire has twice the resistance of the shorter wire. D) The longer wire has four times the resistance of the shorter wire. E) The shorter wire has four times the resistance of the longer wire.
Physics
1 answer:
Makovka662 [10]3 years ago
7 0

Answer:

option (a)

Explanation:

Wire 1:

length = 2L

Area = 2 A

Wire 2: length = L

Area = A

As we know that the resistance of a wire is directly proportional to the length of the wire and inversely proportional to the area of crossection of the wire.

Let ρ be the resistivity of the cooper wire.

Resistance of wire 1

R1 = ρ x 2L / 2 A = ρ L / A

Resistance of wire 2:

R2 = ρ x L /  A = ρ L / A

As R1 = R2

It means both the wires have same resistance.

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Place a pencil or pen in front of you on the surface that you are working on. In one paragraph, using your own words, describe t
Ede4ka [16]

Answer:

READ THIS FIRST!!!

I am not going to right the parragraph (it says to use your own words, they could trace it back to me if you use my words, and you would get it trouble).

But I will tell you the forces acting on the pencil:

Gravity (pulls on the pencil)

Your hand (pushing it up canceling out gravity)

And the electromagnetic force (holding the thing together)

Hope it helped,

Have a good day

4 0
3 years ago
Calculate the total energy of 2.0 kg object moving horizontally at 10 m/s 50 meters above the surface
mina [271]
We have:

Total Energy: KE + GPE
KE (Kinetic Energy) = \frac{1}{2} m*v^2
GPE (Gravitational Potential Energy) = m*g*h

Data:
m (mass) = 2.0 Kg
v (speed) = 10 m/s
h (height) = 50 m
Use: g (gravity) = 10 m/s²

Formula:

Total Energy: KE + GPE
TE =  \frac{1}{2} m*v^2 + m*g*h

Solving:
TE = \frac{1}{2} m*v^2 + m*g*h
TE = \frac{1}{2} *2.0*10^2 + 2.0*10*50
TE =  \frac{2.0*100}{2} + 1000
TE =  \frac{200}{2} + 1000
TE = 100 + 1000
\boxed{\boxed{TE = 1100\:Joule}}\end{array}}\qquad\quad\checkmark


5 0
3 years ago
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What do you mean by Aquatic habitat? Give 2 examples of Desert habitat
Brilliant_brown [7]

Answer:

hope this answer will help you

plzzzz mark me as brainliest

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8 0
4 years ago
Write the ratio of the following?<br><br>CaCO3<br>C2H6<br>Fe(NO3)3​
Triss [41]

Answer:

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4 0
3 years ago
The current in a single-loop circuit with one resistance R is 6.3 A. When an additional resistance of 3.4 Ω is inserted in serie
Dmitry [639]

Answer:

10.15Ω

Explanation:

From ohm's law,

V = IR...................... Equation 1

Where V = Voltage, I = current, R = resistance.

Assume the voltage across the resistance = V,

Given: I = 6.3 A

Substitute into equation 1

V = 6.3R.................. Equation 2

When an additional resistance of 3.4 Ω is inserted in series with R,

The voltage remain the same, but the current changes

Total Resistance(Rt) = (R+3.4)Ω, I' = 4.72 A

Also from ohm' law,

V = I'Rt............... Equation 3

Substitute the value of I'  and Rt into equation 3

V = 4.72(R+3.4)............... Equation 5.

Divide equation 2 by equation 5

V/V = 6.3R/4.72(R+3.4)

1 = 1.335R/(R+3.4)

1 = 1.335R/(R+3.4)

R+3.4 = 1.335R

3.4 = 1.335R-R

3.4 = 0.335R

R = 3.4/0.335

R = 10.15Ω

6 0
3 years ago
Read 2 more answers
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