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Hitman42 [59]
3 years ago
5

What is the side length of a cube with a volume of 64 mm3? Cube V = s3   1. Substitute the value into the formula:      64 = s3

2. Undo the cube by applying the cube root:    3√64 = 3√s3   What is the side length of the cube? mm
Mathematics
2 answers:
rusak2 [61]3 years ago
6 0

Answer:

4mm

Step-by-step explanation:

hope this helps

a_sh-v [17]3 years ago
3 0
The answers is 4mm for the side length of the cube.
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The total cost for a chair, a desk, and a lamp is $562. The desk costs four times as much as the lamp and the chair costs $23 le
alexandr1967 [171]
Ok I’m giving a educated guess here so $562 divided by 3 is 187.3 then you do 187.3-23 which would be 164.3 so if I’m correct it would be 164.3 for both the chair and the lamp and 187.3 for the desk also just a heads up the .3 would be .333333.... :) I will delete if I’m wrong
4 0
3 years ago
The area of a square rug is 64 ft.² what is the perimeter of the rug?
Slav-nsk [51]

Answer:

32{ft}^{2}

Step-by-step explanation:

The area of a square rug = 64 ft²

First we will find the side of square rug = {64}^{2}  =  {s}^{2}

{s}^{2}  =  8

Perimeter of the rug = 4 \times 8= 32ft²

<h3>Hope it is helpful...</h3>
4 0
3 years ago
Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact
umka2103 [35]

Solution:

The permutation formula is expressed as

\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\  \end{gathered}

The combination formula is expressed as

\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\  \\  \end{gathered}

where

\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}

Given that 6 objects are taken at a time from 8, this implies that

\begin{gathered} n=8 \\ r=6 \end{gathered}

Thus,

Number of permuations:

\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}

Number of combinations:

\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}

Hence, there are 28 combinations and 20160 permutations.

7 0
1 year ago
Can someone help pls?
adell [148]

-2x^3-x^2-6x-7

I don't really know what else

6 0
3 years ago
Factor the expression. K^2-16h^2
Tresset [83]

Step-by-step explanation:

{k}^{2}  - 16 {h}^{2}  \\  \\  =  {k}^{2}  - (4 {h})^{2}   \\  \\  = (k + 4h)(k  - 4h)

8 0
3 years ago
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