Answer: 
or 8:17
Step-by-step explanation:
For any angle x (other than right angle) in a right triangle ,the trigonometric ratio of sin x is given by :-
Given: A right triangle with hypotenuse = 68 units
The side adjacent to S = 60
Let h be the side opposite to S, then using Pythagoras in the given right triangle, we get
Thus, the side opposite to S = 32 units
Now, the trigonometric ratio for sin S is given by :-
Hence, the trigonometric ratio for sin S = or 8:17
Answer:
7/11
Step-by-step explanation:
Answer:
294.14cm^2
Explanation:
First find the area of the whole piece of paper:
32*14=448
Then find the area of the two semicircles, semicircle + semicircle = 1 circle:
Area of a circle= (radius squared)(pi):
(7^2)(3.14) = 153.86
Subtract the area of the two semicircles from the whole paper area:
448-153.86 = 294.14
I hope this isn’t too confusing :)
Answer:
$13
Step-by-step explanation:
multiply 65 by 80 then divide by 100, you get 52, so subtract 65 from 52 you get 13
Answer:
ΔABC≅ΔDEC by AAS
Step-by-step explanation:
You can use the AAS method of congruency.
Since you already have <BAC and <EDC congruent to eachother, and sides BC and EC congruent to each other, you only need that one remaining angle in between. <ACB can be proven congruent to <DCE by the Vertical Angles Theorem, and that gives you the AAS you need to prove that these two triangles are congruent
Hope this helped.
