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Savatey [412]
3 years ago
15

The function A(t)=525(1+0.05)^t represents the amount of money in the account after t years. How much more money did Taber origi

nally invest?
Mathematics
1 answer:
saul85 [17]3 years ago
6 0
The amount of money originally invested corresponds to the amount of money at time t=0, so we can find it by putting t=0 inside the equation of A(t):
A(t)=525(1+0.05)^t
So, using t=0
A(0)=525(1+0.05)^0=525 \cdot 1 = 525

So, the amount of money originally invested by Taber is 525.
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Option C:

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Let us solve the term one by one.

$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}

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$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}

$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}

$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}

$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}

Substitute these into the above expansion.

(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}

The coefficient of x^{2} y^{3} is 40.

Option C is the correct answer.

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