Answer:
![Area\ of\ a\ sector = 11\pi\ inches^{2}](https://tex.z-dn.net/?f=Area%5C%20of%5C%20a%5C%20sector%20%3D%2011%5Cpi%5C%20inches%5E%7B2%7D)
Step-by-step explanation:
Given:
The radius of the circle is 6 inches.
And the central angle is 110 degree.
The area of the sector =
-------(1)
Where ![x= central\ angle](https://tex.z-dn.net/?f=x%3D%20central%5C%20angle)
![r = radius](https://tex.z-dn.net/?f=r%20%3D%20radius)
Put radius and central angle value in equation 1.
area of the sector = ![\frac{110}{360}\pi (6)^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B110%7D%7B360%7D%5Cpi%20%286%29%5E%7B2%7D)
area of the sector = ![\frac{11}{36}\pi\times 36](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B36%7D%5Cpi%5Ctimes%2036)
![Area\ of\ a\ sector = 11\pi\ inches^{2}](https://tex.z-dn.net/?f=Area%5C%20of%5C%20a%5C%20sector%20%3D%2011%5Cpi%5C%20inches%5E%7B2%7D)
Therefore, the area of the sector is ![11\pi \ inches^{2}](https://tex.z-dn.net/?f=11%5Cpi%20%5C%20inches%5E%7B2%7D)
Answer:
45
Step-by-step explanation:
Notice how the circle touches both the left and right edges of the square. That given length, 38", creates the <em>diameter</em> of the circle.
To find the area - πr² - you'll need r, the <em>radius, </em>which you can find by splitting the diameter in half, getting a radius of 38/2 = 19".
Using 3.14 as an approximation for π, we get an area of (3.14)(19)² = (3.14)(361) = 1133.54 in²
Answer:
85x
Step-by-step explanation:
Add 4 and 3 . 5 x ( 28 − 4 − 1 * 7 ) Multiply − 1 by 7.
5 x ( 28 − 4 − 7 )
Simplify the expression. Subtract 4 from 28.
5 x ( 24 − 7 )
Subtract 7 from 24.
5 x * 17
Multiply 17 by 5.
85 x
Answer:
Slope: -2
y-intercept: (0, 5)
Step-by-step explanation: