For this case we have the following system of equations:
We observe that we have a quadratic equation and therefore the function is a parabola.
We have a linear equation.
Therefore, the solution to the system of equations will be the points of intersection of both functions.
When graphing both functions we have that the solution is given by:
That is, the line cuts the quadratic function in the following ordered pair:
(x, y) = (1, 2)
Answer:
the solution (s) of the graphed system of equations are:
(x, y) = (1, 2)
See attached image.
Given that:
Consider it is 
instead of 10 on two places.
is between 3 and 4. So, Beau thinks a good estimate for is = 3.5.
Solution:
To find , Beau found 3² = 9 and 4² = 16.
He said that since 10 is between 9 and 16.
Since 10 is close to 9, therefore must be close to 3. So, Beau's estimate is high.
Now,
Since, 10 lies between 9.61 and 10.24, therefore must be lies between 3.1 and 3.2.
Therefore, the estimated value of is 3.15.
Answer:
y ≤ 2x -2 Option C.
Step-by-step explanation:
Equation of the dotted line which passes through (3,0) and (0,8) will be
y = mx+C
m = 
= -1
and C = 3
So equation will be y = x + 3
But shaded blue part is above the dotted line so inequality will be y> -x +3
Equation of the second solid line which passes through ( 0,-2) and (1,0) will be
y = mx + C
m = 
= 
= 2
and C = -2
So equation of the line will be y = 2x - 2
But shaded yellow part is below the solid line.
So inequality will be
y ≤ 2x -2
Option C. is the answer.
Given two points A(x₁,y₁) and B(x₂,y₂) the distance betwen these points will be:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²].
We have these points: A(0,0) and B(6,3); its distance will be:
dist(A,B)=√[(6-0)²+(3-0)²]
=√(6²+3²)
=√(36+9)
=√45 ≈ 6.71
Answer: D. 6.71 units.
Answer:
where 
= 2
Step-by-step explanation:
512/-8 = -64
difference of n = 3
![\sqrt[3]{64} = 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%204)
where = 2
